THE FIFTH ORBIT OF SUN FROM OF FIVE MINUTE DISTANCE.

FIRST MUTE ORBIT OF SUN. 

The fifth orbit of sun is first Mute orbit. and it is five minute away from the sun. here are not any special activity of sun particle.      

Rate of Orbit. 

we shall solve this matter with light speed. but you should know about light speed. and it is not very difficult. Number one, A star`s temperature of surface always happens 15000000 Centigrade. and always into one proton are happens five photons. and 

the light speed begins from one meter, one seconds. when we shall divide the sun surface temperature with five photons. then one heated particle would be divided. and when we multiply with 100 centimetres. then will be begun the travel of ray. 

First Basic Law. 

Temperature of sun`s surface is ‘‘15000000 Centigrade’’ / 300000000 light speed per meter seconds = 0.05 x 100 centimetre = 5 photons of one proton. 

Second Basic Law. 

I know it that 0.05 is very cheap value of any mass. because it is the heat value of mass. and photons happens very small. to which you cannot see. only can be feel them. So one photon mass equal to .008. So then 0.05 / .008 = 6.25 / 1.25 Earth hydrogen mass unit = 5 photons of one proton. 

Third Basic Law. 

Temperature of sun`s surface is ‘‘15000000 Centigrade’’ / 12.5 mass unit of sun hydrogen atom = 1200000 x  .008 hot photon = 9600 x .008 cold photon = 76.8 / 60 minute = 1.28 - 0.03 = 1.25 mass unit of earth`s hydrogen.  

Fourth Basic law.  About light speed

Stars`s surface temperature 15000000 / 5 Photons or one Neutron = 3000000 x 100 Centimetres   = 300000000 light speed meter per seconds. 

Fifth nearest orbit of Sun.  

Sun`s fifth orbit which belongs with quite atmosphere. this orbit is five minute far from sun. and five minute are equal to 300 seconds. So 300 x 300000000 = 9.0000000000 meters distance from sun.. and to the know days. 9.0000000000  / 24 hour / 60 minute / 1000000 light  

measure = 62.5 days of quite orbit of sun. Now to the orbit. 9.0000000000 x 6 = 5400000000000 meter orbit. to the know days. 5400000000000 / 24 hours / 360 degree / 1000000 light measure = 62.5 days of orbit. 

NOT ANY SATELLITE EXIST HERE.

But I am doing solve value of each orbit. even which orbit is away from the sun. So it is fifth orbit of sun. If in future you made a humans colony into space. then you can acquire the energy from even any orbit of sun. 

Diameter of Satellite. 

If the satellite diameter proper and perfect. then they will right rotate around the sun. and it is first important matter. because which you make the satellites to rotate around of sun. their size will nearly equal to two moon. So orbit radius is 300 seconds from sun. in which 

satellite will be sent. So 300 x 21.78 code of diameter = 6534 kilometres diameter of the satellite. and by radius that 6534 / 6 = 1089 kilometres. and it is two percent big from our moon. Because total seconds are 300 x 3.63kg length weight = 1089 / 17.424 Code of days = 62.5 days of orbit.       

DIAMETER OF EARTH. 

1752 is the distance of earth in the light seconds. So 1752 x 21.78 Code of diameter = 38158.56 kilometres. diameter of Earth. and radius is 6359.76 kilometres. or, 38158.56 / 6 = 6359.76 kilometres radius of earth.  

TEMPERATURE OF SATELLITE. 

Who metal will use you to the satellite. which could bear the sun temperature. because orbit of five seconds far  from sun.would have to be very warm, you will have to use special metal. Although Mercury`s temperature is 503 Centigrade. and Mercury is 6.9 minute away from sun. Now we are going to solve of temperature of  

satellite. perhaps would have remember you law oftemperature. ( that light speed / distance in seconds / 24 hours / 60 minute = temperature of planet). So satellite or orbit`s distance is 300 seconds. Then 300000000 / 300 =  1000000 / 24 = 4166666667 / 60 = 694.44 Centigrade temperature will happen of satellite or of the orbit. and it is right and perfect temperature. because when we ll’ divide Mercury temperature with the satellite or of the  orbit temperature. 

then our proof will be strong. So satellite temperature is 694.44 / 503 = 1.380 x 5 minute = 9.6 minute distance of Mercury  from the sun. here we shall say. if your basic maths would have to be right. then you can solve each matter of universe. Now we have 694.44 Centigrade temperature to the satellite or of the orbit. If you are thinking that it is too much  temperature. then you are wrong. because which maths I am going to tell you. that our problem will be solved About space.. 

WHAT IS THE GRAVITY IN UNIVERSE. 

As count this satellite will happen two percent big from our moon. which is important point here. The sun diameter is 4833.26 days kilometres. and it is a vast diameter. So 300 seconds or 5 minute away from sun. we are doing calculation of which orbit. which is very close from the sun. from this reason that from here the very less rotation would have to be started

 ABOUT MASS REACTION OR GRAVITY.  

A exist in each planet, moon and stars the reaction of mass. but their value are different in our universe. I made a law for this. which is very easy. 1. FOR STAR, to the normal size`s star. the Mass reaction would to be 300,000. kilometres till from on surface. or one light seconds Mass reaction from on surface of the star. and. here are being some Misunderstanding. you should wait for it.  

THE VELOCITY OF SATELLITE IN OWN ORBIT. 

The satellite`s velocity will happen 193.33  kilometres per seconds in own orbit. and it velocity is 5 percent excessive from the sun diameter. So it is finally accurate law of velocity. Now to the make law we ll’ use the sun diameter and atom two conditions. So satellite days are 50 in own orbit. next 1.25 is warm condition 

of Hydrogen atom and 1.25 is cool condition of atom. after collect both. 1.25 + 1.25 = 2.5. Now satellite total days are 62.5 / 2.5 = 25 and it is the code of speed. The sun diameter is 4833.26 days kilometres. So 4833.26 / 25 speed code = 193.33 kilometres per seconds. I had explained about velocity of planet 2.5 years ago. which. 

was fifty percent accurate. and it law is hundred percent accurate . Actually! I am explaining about many subject in same time. So can be mistake but I itself shall do accurate own each mistake. And in the beginning the Internet and english  were new things for my.   

VELOCITY OF EARTH. 

The earth days are 365 / 2.5 = 146 and sun diameter 4833.26 / 146 = 33.10 kilometres velocity per seconds around the sun of earth.   

THE SIZE OF SUN FROM FIVE MINUTE DISTANCE. 

It is also very important matter. you always see the sun in 1.5 feet size from the earth. but if you want imagin size of sun from five minute away. then this law will help us. many events rises up into the Universe. sometimes a star suddenly very quickly  melt to be the small size. fact about a star. which was against across of our solar system in

the milky-way. and around this star the life were exist in two planets. there in only four centuries. their star was fifty percent melt. from this reason. there life was suddenly finished into the two planets. why it happened, actually you do not know about the starQuake which happens very dangerous. tell later to which details. So we are doing probe of sun 

from five minute away. So from five minute away the sun size will happen 13.33 feet. Now by maths is that the sun diameter is 4833.26 days kilometres. So 4833.26 / 300 seconds = 16.11086667 and we shall only use 16 here. So 16 x 10 atom = 160 inch. and by the feet that 160 inch / 12 = 13.33 feet height of sun from five minute away. or, size of sun.