LAST ELECTRON OF ‘‘YTTRIUM’’ WITH CROSS-TRON

WITH ENERGY LAW  ‘‘E = m + m x C1’’

39 last electron of ‘‘Yttrium’’ Perhaps for this reason his says atomic number 39. Or` atomic number 39 meaning last electron of ‘‘Yttrium’’ So Electron number 39 have also one orbit. and his connect was also with sector 9000L like our earth. and` we 

shall solve motion of last electron with planets motion. we would get here four information. (1) Electron energy. (2) Electron orbit. around the atom (3) micro meter distance between Electron and ‘‘Yttrium’’ level till. (4) micro seconds distance 

between Electron and ‘‘Yttrium’’ But before the begin. I want some tell you, about Atomic number. with a simple method. Our earth have 365 days, But` if sees to his, like a atomic theory. Then sun is like a atom and Earth is a Electron and his atomic number 

is 365. Perfectly like this ‘‘Yttrium’’ is a atom and his last electron is his atomic number 39 Last electron of  ‘‘Yttrium’’ that in last Electron revolves around with micro meter speed. after of all.

EARTH HOT AND COLD PERIOD, 

So E = m + m x C1. Earth was hot in begin and Earth has cold now. m365 hot + m365 cold = 730 x C1 300000000 = 2.19000000000 x .008 photon = 1752000000 / 1000m / 100m /10mm = 1752 seconds distance between Earth and Sun. Now` we 

shall make his distance in meters and orbit. 1752 x 300000000 = 525600000000m and` it is distance in meters. 525600000000 x 6 = 3153600000000m and` it is orbit of Earth. Now` to this orbit` we shall do shift in atom number. (1) electron has not 

moon, (2) electron has not days months and year. from this reason` orbit of electron we shall divide with 24 hours and 360 degrees. 3153600000000m / 24 / 360 degrees = 365000000 / 1000m / 100m / 10mm = 365 atomic number. Or` 365 atomic number of Earth. now

LAST  ELECTRON OF ‘‘YTTRIUM’’ AND, E = m + m x C1. 

‘‘Yttrium’’ atomic number 39. So m39 hot + m39 cold = 79 x C1, 300000000 = 23400000000 x .008 one photon = 187200000 / 1000m / 100m /10mm = 187.2 is micro seconds distance between last electron. and 23400000000  volt energy of last 

electron of ‘‘Yttrium’’ Now` we shall make his distance in micro meter 187.2 x 300000000 =  56160000000 / 1000mc / 100mc /10mc = 56160 it is the distance in micro meters between last electron and ‘‘Yttrium’’ surface till. to the proof  56160 / 24 hours  / 60 minute 

= 39 electron of ‘‘Yttrium’’ Now` we shall make to his orbit. 56160 x 6 = 336960 so it is orbit of last electron. in the micro meter measurement. (  Now to the atomic number ) we shall make his atomic number. 336960 orbit / 24 hours = 14040 / 360 degrees = 39 atomic Number of ‘‘Yttrium’’      

DETAILS OF ELECTRON OF ‘‘YTTRIUM’’  

(1) electron energy  23400000000 volt. (2) electron orbit 336960 micro meter. (3)  56160 is micro meter distance between last electron and ‘‘Yttrium’’ level till. (4) 187.2 micro seconds distance between last electron and ‘‘Yttrium’’     

PROOF OF DETAILS.  

1. one electron charge 14.4 and one proton charge 25 percent excessive from electron. 

1. 23400000000 volt / 14.4 = 1625000000 x .008 = 13000000 / 1000000 = 13 + 12 = 25 

percent excessive charge of proton from one electron.

2. we shall compare between hydrogen size and electron charge. with micro meter distance 56160 

2. 56160 / 1.25 hydrogen size = 44928 / 60 seconds hydrogen time = 748.8 / 100 area =  7.488 + 6.912 = 14.4 electron charge.

3. orbit, we shall to know percentage of electron charge here. with photon quantity. in one 

proton happens 5 photons. 

3. 336960 / 5 = 67392 / 360 degrees = 187.2 / 25 proton percentage = 7.488 +  6.912 = 

14.4 active charge.  

4. we shall to know percentage of charge with proton charge 28.8. 

4. 187.2 micro meter distance. So 187.2 / 28.8 = 6.5 + 6 = 12.5 Sun hydrogen atom size  

 LAST ELECTRON OF ‘‘YTTRIUM’’ AND CROSS-TRON.

If the electron charge value would be right. then will be solved automatically time of mass and weight of mass through the new energy law. So ‘‘Yttrium’’ atomic seconds distance 187.2 and one electron charge 14.4 and energy law E = m + m x C1. Now, m14.4 + m187.2 = 201.6 x 300000000 = 60480000000 / 24 hours / 60 minute / 1000m / 100cm light measure = 420 / 123.52  light code = 3.4 Cross-tron of ‘‘Yttrium’’ Now to the work condition ‘‘Yttrium’’ will have need 123.52  volt 

energy for one atom and you will be get 23400000000 volt energy from one atom. But how` when we shall be reached at Hydrogen atom till then you will understood. and Every maths is possible! If you have right atomic energy law. You know very well that i test at earth first of all. and second at atom. and third at human body.