Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jul 17th 2017, 11:32 am
Posted by aqeelsika
534 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Methane 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 17% * H0.01 of fusion = 0.17 hour 

 

                       Because 

                       Hour = 0.17 * 48 proton of Cd = 8.16-Oxygen   

                            = 8.16 – 6 proton of C = 2.16-Hydrogen 

 

Oxygen = 8 proton    

Hydrogen = 2.16 proton 

Total = H2O = water 

 

Carbon = 8.16 * 2.16 = 17.6256

       = 17.6256 - 0.6256 () = 17

       = 17

 

Chemical = 17 – 5 (H4) Organic synthesis type atmosphere of earth = 12

         = 12 = C = Carbon  

 

Organic synthesis type atmosphere, usually by the union of simple chemical compounds,   

 

Chemical formula from 0.62 hours = CH4

                                 = CH4, Methane 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 170.206 (CH4)10 = 170) = 17

                      = 17 = CH4 = (E = m2c),  

 

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