ADSORBENTS OF 40 YEAR AGE
SYNTHESIS OF DISEASE
WITHOUT DRUGS GENETIC TREATMENT
(Auto DNA Engineering)
Adsorbents! Solids which attract gases or dissolved substance, to their surface, charcoal absorbs gases and acts as a deodorant, kaolin adsorbs bacteria and other toxins, hence used in Food poisoning,
SILENT RESEARCH
1 = Adsorbents = when Methionine becomes less in body, then bacteria and toxins gather on surface of food and into the liver, when Threonine becomes less in body then poisoning gather on surface of food with bacteria,
1 = without drug = Methionine amino acid deficiency = bacteria and toxins,
2 = without drug = Threonine amino acid deficiency = poisoning with bacteria,
Normally
A1 = Human digestive system has a map of 206 bones for control bacterial toxins and poisoning diseases,
A2 = when human digestive system lost map of 206 bones then they lost control of bacterial toxins and poisoning, like food drink and breathing poisoning,
mRNA 1 to 64 codon = normal function of body = normal speed of growth
mRNA 66 to 100 codon = abnormal function (Abnormality) and fast speed of growth,
WITHOUT DRUG TREATMENT
1 = Adsorbents = Methionine + Threonine
1 = Methionine + Threonine TAC + TGA, TGG, TGT, TGC, (DNA base)
1 = Methionine + Threonine = A2 + T6 + C2 + G5
1 = Methionine + Threonine = A-270.26 + T-756.66 + C-222.2 + G-755.65
1 = Methionine + Threonine DNA base = 2004.77
2 = Methionine + Threonine = 151.75 m/g + 121.25 m/g = 273
1 = Methionine + Threonine = 273
2 = Methionine + Threonine DNA base = 2004.77 = (A-T=C-G)
3 = Adsorbents = Methionine + Threonine safety of poisoning toxin and bacteria,
ANSWER OF DISORDER
Too Sick disorders
FORMULA TO FIND OUT MEDICINE OF DISEASES
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SYNTHESIS OF DISEASE
WITHOUT DRUGS GENETIC TREATMENT
Methionine + Threonine = 273 mole gram
Methionine + Threonine DNA base = 2004.77
Adsorbents = Methionine + Threonine safety of poisoning toxin and bacteria,
Met + Thr DNA base = 2004.77 – 273-Met + Thr = 1731.77
= 1731.77 / 41.61 = 41.61
= 41.61 + 0.89 () = 42.5
= 42.5 = Nearly CaH2 = Calcium hydride,
The Calcium hydride mostly used as reducing agent like reducing poisoning and toxin effect, and source of hydrogen
FOOD POISONING AND BIOLOGICAL CHANGES
40 year age biological changes = 800 / 42.5 = 18.82
5 year age biological changes = 100 / 42.5 = 2.35
Calcium hydride = 42.5 * 18.82 (Food poisoning and 40 year age) = 799.85
Calcium hydride = 42.5 * 2.35 (amino acids and 5 year age) = 99.875
Total Food poisoning + amino acids = 899.725
Total Food poisoning = 899.725 + 625.6386 (normal 4.18 Lysine) = 1525.3636
40 year age can cover quickly to food poisoning from reason of 4.18 Lysine in body then the 90 year age, per Lysine = 149.5
If you go in more down in 20 year age, then there would be more much Lysine, because ** has powerful amino acid sets, and child has too much powerful amino acid sets,
MOST IMPORTANT
Always remember before sleep and after get up, that all amino acid will be counted in minus (-) for large age and all amino acid will be counted in plus (+) for medium age, while ** and child has complete sets of amino acid,
Met + Thr = 273
Food poisoning = 1525.3636
Met + Thr-273 m/g mRNA CODE
Met + Thr-273 + 1525.3636 (Food poisoning) = 1798.3636 mole / 1525.3636 (Food poisoning) = 1.17% absorb gases and toxins,
1.17 * 1525.3636 (Food poisoning) = 1784.675412
1.17 times gases and toxins = 1784.675412
TO START GENETIC SYSTEM
Met + Thr = 273
Food poisoning = 1525.3636
1.17 times gases and toxins = 1784.675412
Uracil = C4H4N2O2 = 112.0868 g/mol = (U)
a2 + b2 [3Th part] = c2
a2 + b2 (amino acid) = c2
a2 (Uracil) + b2 (60 minute) [amino acid] = c2
a2 (112.0868) + b2 (60 minute) [amino acid] = c2
a2 (12563.45073424) + b2 (3600) [amino acid] = c2
a2 + b2 = 16163.45 [amino acid] = c2
a2 + b2 = 16163.45 / 127.13 = 127.14
a2 + b2 = 127.14 * 1784.675412 (1.17 times gases toxinc) = 226903.63188168
a2 + b2 = 226903.63188168 / 3 triple RNA = 75634.54396056
a2 + b2 = 75634.54396056 - 73741.83036056% (Met + Thr-273) = 1892.7136
a2 + b2 = 1892.7136 = AUG + ACU ACC ACA ACG = Met+Thr from Food poisoning
Met + Thr = 73741.83036056% / 273 Met+Thr = 270.11 sets in mRNA
Met + Thr = AUG + ACU ACC ACA ACG = 1892.7136
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JOINING OF ADENINE WITH THYMINE
JOINING OF GUANINE WITH CYTOSINE
WHAT IS PRESENCE OF METAL IN CELL FLUID?
Met + Thr = AUG + ACU ACC ACA ACG = 1892.7136 – 1525.3636 Food poisoning = 367.35
Start
a2 + b2 = 16163.45 / 367.35 (Met+Thr - Food poisoning) = 44.00 or 44 amino codon to take start from AAA-Lysine mRNA
End
a2 + b2 = 2113.8936 Met+Thr = 40 = AUG+ACG-Met+Thr end mRNA
JOINING OF ADENINE GUANINE = PURINE
JOINING OF URACIL CYTOSINE = PYRIMIDINE
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FOR STOP TO RNA
If started from left side to codon chart
Then Start = AAA-Lysine mRNA = 44 amino acid,
Then End = AUG+ACG-Met+Thr mRNA = 40 amino acids,
AUG-Met position is 12 numbers in Helix
ACG-Thr position is 28 numbers in Helix
Total position = 40
Or to make protein under the Met+Thr + Lysine use only 4-UUG-Leucine codes of RNA,
Start = 44 – 40 End = 4-UUG-Leucine codon RNA
End position = 12 * 28 start = 336
= 336 * 40 link of proteins = 13440
= 13440 m/g or 14,300 Lysozyme-chicken proteins
Lysozyme-chicken proteins! An enzyme found in saliva and sweat and tears that destroys the cell walls of certain bacteria,
SOLUTION OF DISEASE
Start AAA-Lysine
End AUG+ACG-Met+Thr
Center UUG-Leucine
Total codon = AAA-AUG-ACG-UUG
Start AAA-Lysine proteins! Treatment of Herpes Simplex, A herpes virus that affects the skin and nervous system from toxins
End AUG-Met proteins! Assists in breakdown of fats, Assists in the removal of toxic wastes from the liver and stomach,
End ACG-Thr proteins! Acts as detoxicate,
Center UUG-Leucine proteins! Works in conjunction with Vitamin C in keeping skin and joints healthy,
GENETIC TREATMENT AND MEDICINE FORMULA
DOCTORATE OF AMINO ACID
1.17 Times gases toxin + 270.11 sets Met+Thr + Lysine = Food poisoning treat/ AAA-AUG-ACG-UUG,
Gases and toxin = +1.17 m/g
Met+Thr = +270.11 m/g
Lysine = -171.28 m/g
Total = 100 m/g = Food poisoning treat / AAA-AUG-ACG-UUG, in 40 year age
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BIOLOGICAL CHANGES
ABOUT 40 YEAR AGE
40 year age * 20 amino acid = 800 change =
If = 40 year * 365 day of year = 14600
= 14600 total day of 40 year age
= 14600 / 800 total change = 18.25
= 18.25 + 0.25 - 18.5
= 18.5 = H2O = water
ALGEBRAIC VALUE OF 90 YEAR
= a2 + b2 = c2
= a 40 year age + b 800 ninety change = c2
= a40 + b800 = c2
= 1600 + 640000 = c2
= a + b = 641600 = c2
= a + b = 641600 / 801 = 800.98
= a + b = 800.98 * 18.23 (H2O) = 14601.8654
= a + b = 14600 day of 40 years
= 40 year age belongs with 18.23 (H2O) by fixed biology