ATMOSPHERE OF CARBON ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Dimethyl ether 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

        a2 (36)          + b2 (36) = c2

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

Carbon energy atmosphere = 47.5% * H0.01 of fusion = 0.475 hour 

                       Because 

                       Hour = 0.475 * 23 proton of V = 10.925-Sodium   

                            = 10.925 – 6 proton of C = 4.925-Boron 

Sodium = 11 proton    

Boron = 5 proton  

Carbon = 10.925 * 4.925 = 53.805625

       = 53.805625 - 6.305625 (H5 = 6.25) = 47.5

       = 47.5

Chemical = 47.5 – 16 (O) Dimethyl ether type atmosphere of earth = 31.5

         = 31.5 – 7.5 (H6) = 24

         = 24 = C2 = Carbon  

Dimethyl ether type atmosphere,    

Chemical formula from 0.475 hours = CH3OCH3

                                   = CH3OCH3, Dimethyl ether  

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 60.916 (3H2O + H4 = 60.5) = 47.5

                      = 47.5 = CH3OCH3 = (E = m2c),