Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jun 21st 2017, 11:31 am
Posted by aqeelsika
520 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Acetic acid 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 61% * H0.01 of fusion = 0.61 hour 

 

                       Because 

                       Hour = 0.61 * 19 proton of k = 11.59-Magnesium   

                            = 11.59 – 6 proton of C = 5.59-Carbon 

 

Magnesium = 12 proton    

Carbon = 6 proton  

 

Carbon = 16.02 * 10.02 = 160.5204

       = 160.5204 - 27.0204 (2CH + 0.250625 = 26.5) = 61

       = 61

 

Chemical = 61 – 32 (O2) Colorless type atmosphere of earth = 29

         = 29 – 5 (H4) = 24

         = 24 = C2 = Carbon  

 

 

Colorless atmosphere,   

 

Chemical formula from 0.61 hours = CH3COOH

                                 = CH3COOH, Acetic acid 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 47.4345 (CO2 + H2.74 = 46.74) = 61

                      = 61 = CH3COOH = (E = m2c),  

 

Bookmark & Share:

Please Like Us
Please Like Us