Sikander Aqeel

SECOND RNA BASE LAW OF SIKANDER AQEEL

Jun 16th 2017, 11:27 am
Posted by aqeelsika
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SECOND BASE OF RNA  

ADENOVIRUS 

SYNTHESIS OF DISEASE  

WITHOUT DRUGS GENETIC TREATMENT 

(Auto DNA Engineering)     

Adenovirus! Are medium-sized (90–100 nm), nonenveloped (without an outer lipid bilayer) viruses with an icosahedralnucleocapsid containing a double stranded DNA genome. Their name derives from their initial isolation from human adenoids in 1953,

They have a broad range of vertebrate hosts; in humans, more than 50 distinct adenoviral serotypes have been found to cause a wide range of illnesses, from mild respiratory infections in young children (known as the common cold) to life-threatening multi-organ disease in people with a weakened immune system,

 

SILENT RESEARCH 

Threonine = (Thr) production of antibodies, Can be converted to Glycine (a neurotransmitter) in the central nervous system, Acts as detoxicate, remove poison of viruses,    

 

Heart diseases

A1 = every respiratory cell has a map of 206 bones for normal respiratory function, 

A2 = when respiratory cells lost map of 206 bones then becomes start respiratory infection from virus, 

 

mRNA 1 to 64 codon = normal function of body = normal speed of growth 

mRNA 66 to 100 codon = abnormal function (such as  tonsils) and fast speed of growth,  

 

WITHOUT DRUG TREATMENT  

1 = Adenovirus act = mRNA 66 to 100 codon or (over cold respiratory)      

 

1 = Threonine = TGA, TGG, TGT, TGC, (DNA base)

1 = Threonine = A1 + T5 + C1 + G5  

1 = Threonine = A-135.13 + T-630.55 + C-111.1 + G-755.65

1 = Threonine DNA base = 1632.43

 

2 = Threonine = C4H9NO3 = 121.25 m/g 

 

1 = Threonine = 121.25

2 = Threonine DNA base = 1632.43 = (0-T=C-0) 

3 = Virus care = 10.60 helix = 5550.6462 mole  

3 = Virus care = 10.60 helix = 5 double helix  

 

For example Adenovirus infection = 10.60 helix * 523.47 human per helix = 5548.782 

 

ANSWER OF DISORDER 

Too Sick disorders 

FORMULA TO FIND OUT MEDICINE OF DISEASES

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ADENOVIRUS 

SYNTHESIS OF DISEASE  

WITHOUT DRUGS GENETIC TREATMENT 

       Threonine = 121.25 mole gram               

       Threonine DNA base = 1632.43 

       Virus care = 10.60 helix = 5550.6462 mole  

       Virus care = 10.60 helix = 5 double helix  

       Adenovirus = mRNA 66 to 100 codon or (over cold of respiratory)  

 

 

Threonine DNA base = 1632.43 – 121.25-Threonine = 1511.18

                = 1511.18 / 38.87 = 38.87

                = 39 = K = Potassium 

 

Potassium = 39 * 28.6788 (2CH2+H2 = 29) = 1118.4732

 

Virus care = 1118.4732 = (A-T=C-G)2 + OH4 + H2 = 1118.44 

 

 

Here 1118.4732 will be counted for human double helix, 

 

Threonine-121.25 production of antibodies, Can be converted to Glycine (a neurotransmitter) in the central nervous system, Acts as detoxicate, remove poison of viruses   

 

Virus care-1118.4732! Without Infections or without virus body,    

 

Threonine-121.25 m/g mRNA CODE    

Threonine-121.25 + 1118.4732 (care) = 1239.7232 mole / 1118.4732 (care) = 1.10 without virus,  

 

1.10 * 1118.4732 (care) = 1230.32052

1.10 times without virus = 1230.32052

 

TO START GENETIC SYSTEM 

Threonine-121.25

Virus care-1118.4732

1.10 times without virus = 1230.32052

 

Uracil = C4H4N2O2 = 112.0868 g/mol = (U) 

 

        a2 + b2 [3Th part] = c2  

        a2 + b2 (amino acid) = c2  

 

        a2 (Uracil)           + b2 (60 minute) [amino acid] = c2  

        a2 (112.0868)         + b2 (60 minute) [amino acid] = c2   

        a2 (12563.45073424)   + b2 (3600) [amino acid] = c2 

 

        a2 + b2 = 16163.45 [amino acid] = c2 

        a2 + b2 = 16163.45 / 127.13 = 127.14 

 

      a2 + b2 = 127.14 * 1230.32052 (1.10 times without virus) = 156422.9509128

      a2 + b2 = 156422.9509128 / 3 triple RNA = 52140.9836376

      a2 + b2 = 52140.9836376 - 50646.6168376% (Threonine-121.25) = 1494.3668

      a2 + b2 = 1494.3668 = ACU ACC ACA ACG = Thr from without virus,  

 

Threonine = 50646.6168376% / 121.25 Thr = 417.70 sets in mRNA   

Threonine = ACU ACC ACA ACG = 1494.3668

 

        JOINING OF ADENINE WITH THYMINE 

        JOINING OF GUANINE WITH CYTOSINE

 

WHAT IS PRESENCE OF METAL IN CELL FLUID?  

Threonine = ACU ACC ACA ACG = 1494.3668 Thr – 1118.4732 Virus care = 375.89

 

      Start 

      a2 + b2 = 16163.45 / 375.89 (Thr – Virus care) = 43 or 43 amino codon to take start from AAA-Lysine mRNA 

 

      End 

      a2 + b2 = 1494.3668 Thr = 28 = ACG-Threonine end mRNA 

 

        JOINING OF ADENINE GUANINE = PURINE 

        JOINING OF URACIL CYTOSINE = PYRIMIDINE 

 

 

        FOR STOP TO RNA 

        If started from left side to codon chart 

        Then Start = AAA-Lysine mRNA = 43 amino acid, 

        Then End = ACG-Threonine = 28 amino acids,  

 

 

Or to make protein under the Threonine + Threonine use only 15-GUA-Valine codes of RNA, 

Start = 43 – 28 end = 15-GUA-Valine codon RNA 

 

ADENOVIRUS 

SOLUTION OF DISEASE

Start AAA-Lysine = A = Second base

End ACG-Threonine = A = Second base

Center GUA-Valine = G = Second base 

 

AAA-Lysine protein, Inhibits viral growth, 

 

ACG-Threonine protein, production of antibodies, Can be converted to Glycine (a neurotransmitter) in the central nervous system, Acts as detoxicate, remove poison of viruses,

 

GUA-Valine protein, all of which are involved with muscle strength, endurance, and muscle stamina,

 

 

SECOND CODE READING LAW FOR HEALTH 

Up to down = AAG -------rain fall from sky like up to down 

Down to up = GAA -------water go up through the roots of plant 

Central point= AAG AGA – center up to down and down to up 

 

Total codon = AAG GAA AAG AGA  

 

TRANSFORMATION OF CODE FOR HEALTH    

GENETIC MUTATION

mRNA protein AAG-Lysine! Inhibits viral growth, 

 

mRNA protein GAA-Glutamic! neurotransmitters

 

mRNA protein AAG- Lysine! Inhibits viral growth, 

 

mRNA protein AGA-Arginine! Essential for normal immune system activity,

 

HEREDITY DISEASES 

Total codon = AAGGAAAAGAGA = A8 * G4 = 32 pair codon of normal mRNA 

 

Total mRNA AA-GG-AA-AA-GA-GA

Total sex of codons (GA-XY)( GA-XX) + (AA-XX) (GG-XX)( AA-XX)(AA-XX) 

Female = 4 sets of Chromosomes (XX-XX-XX-XX) Autosome 

Male = 2 sets of Chromosomes (XY-XY) Autosome,  

 

By Lysine and Threonine amino acid female 4 set help to protect of virus and male 2 sets help to protect of virus in child and ** body 

 

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