Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jun 16th 2017, 11:26 am
Posted by aqeelsika
546 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Acetate ion 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 59.75% * H0.01 of fusion = 0.5975 hour 

 

                       Because 

                       Hour = 0.5975 * 20 proton of Ca = 11.3525-Sodium   

                            = 11.3525 – 6 proton of C = 5.3525-Boron 

 

Sodium = 11 proton   

Boron = 5 proton  

 

Carbon = 11.3525 * 5.3525 = 60.76425625

       = 60.76425625 - 1.01425625 (H = 1.25) = 59.75

       = 59.75

 

Chemical = 59.75 – 32 (O2) Acetate fibers type atmosphere of earth = 27.75

         = 27.75 – 3.75 (H3) = 24

         = 24 = C2 = Carbon  

 

 

Acetate fibers type atmosphere, A fiberic made from cellulose acetate fibers,      

 

Chemical formula from 0.5975 hours = CH3COO−

                                   = CH3COO−, Acetate ion 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 48.426 (H2O2 + CH = 47.75) = 59.75

                      = 59.75 = CH3COO− = (E = m2c), 

 

 

 

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