Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jun 15th 2017, 11:16 am
Posted by aqeelsika
567 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Acetamide 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 60.25% * H0.01 of fusion = 0.7875 hour 

 

                       Because 

                       Hour = 0.6025 * 20 proton of Ca = 12.05-Magnesium   

                            = 12.05 – 6 proton of C = 6.05-Carbon 

 

Magnesium = 12 proton   

Carbon = 6 proton  

 

Carbon = 12.05 * 6.05 = 43.45380625

       = 72.9025 - 12.6525 (CH = 13.25) = 60.25

       = 60.25

 

Chemical = 60.25 – 16 (O) Organic compound type atmosphere of earth = 44.25

         = 44.25 – 6.25 (H5) = 38

         = 38 – 14 (N) = 24    

         = 24 = C2 = Carbon 

 

 

Organic compound type atmosphere, A colorless solid amide of acetic acid used as a solvent and in the synthesis of organic compound,      

 

Chemical formula from 0.6025 hours = CH3CONH2

                                   = CH3CONH2, Acetamide 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 48.025 (H2O2 + CH = 47.75) = 60.25

                      = 60.25 = CH3CONH2 = (E = m2c), 

 

 

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