Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jun 13th 2017, 10:59 am
Posted by aqeelsika
522 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Acetone 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 63.5% * H0.01 of fusion = 0.635 hour 

 

                       Because 

                       Hour = 0.635 * 13 proton of Al = 8.255-Oxygen   

                            = 8.255 – 6 proton of C = 2.255-Helium 

 

Oxygen = 8 proton   

Helium = 2 proton 

 

Carbon = 20.51 * 2.255 = 297.6001

       = 18.615025 - 44.884975  (CO2 + H = 45.25) = 63.5

       = 63.5  

 

Chemical = 63.5 – 32 (O2) Simplest ketone type atmosphere of earth = 31.5

         = 31.5 – 7.5 (H6) = 24  

         = 24 = C2 = Carbon 

 

 

Simplest ketone type atmosphere, carbon familly of organic compounds,      

 

Chemical formula from 0.635 hours = CH3COCH3

                                  = CH3COCH3, Acetone 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 45.56 (CO2 + H = 45.25) = 63.5

                      = 63.5 = CH3COCH3 = (E = m2c), 

 

 

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