Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jun 10th 2017, 11:42 am
Posted by aqeelsika
529 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Stearic acid 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 293% * H0.01 of fusion = 2.93 hour 

 

                       Because 

                       Hour = 2.93 * 7 proton of N = 20.51-Scandium   

                            = 20.51 – 6 proton of C = 14.51-Phosphorus 

 

Scandium = 21 proton   

Phosphorus = 15 proton 

 

Carbon = 20.51 * 14.51 = 297.6001

       = 297.6001 - 4.6001 (H3.6 = 4.5) = 293

       = 293 

 

Chemical = 293 – 32 (O2) Vegetable fats type atmosphere of earth = 261

         = 261 – 45 (H36) = 216  

         = 216 = C18 = Carbon 

 

 

Vegetable fats type atmosphere, such as whole world eating Vegetable,      

 

Chemical formula from 2.93 hours = CH3(CH2)16COOH

                                 = CH3(CH2)16COOH, Stearic acid 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 9.8754 (H7.9 = 9.875) = 293

                      = 293 = CH3(CH2)16COOH = (E = m2c), 

 

 

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