Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jun 8th 2017, 11:38 am
Posted by aqeelsika
579 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Diethyl ether, Ethoxyethane 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 76.5% * H0.01 of fusion = 0.765 hour 

 

                       Because 

                       Hour = 0.765 * 13 proton of Al = 9.945-Neon   

                            = 9.945 – 6 proton of C = 3.945-Beryllium 

 

Neon = 10 proton   

Beryllium = 4 proton 

 

Carbon = 9.945 * 3.945 = 39.233025

       = 39.233025 + 37.266975 (2H2O = 37) = 76.5

       = 76.5

 

Chemical = 76.5 – 16 (O) Inhalation type atmosphere of earth = 60.5

         = 60.5 – 12.5 (H10) = 48  

         = 48 = C4 = Carbon 

 

 

Inhalation type atmosphere, or act of breathing in,      

 

Chemical formula from 0.765 hours = CH3CH2OCH2CH3

                                  = CH3CH2OCH2CH3, Diethyl ether, Ethoxyethane 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 37.8236 (2H2O + H = 38.25) = 76.5

                      = 76.5 = CH3CH2OCH2CH3 = (E = m2c), 

 

 

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