Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jun 5th 2017, 11:21 am
Posted by aqeelsika
551 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

1-Propanol 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 62% * H0.01 of fusion = 0.62 hour 

 

                       Because 

                       Hour = 0.62 * 13 proton of Al = 8.06-Oxygen   

                            = 8.06 – 6 proton of C = 2.06-Helium 

 

Oxygen = 8 proton   

Helium = 2 proton 

 

Carbon = 8.06 * 2.06 = 16.6036

       = 16.6036 + 45.3964 (COOH = 45.25) = 62

       = 62

 

Chemical = 62 – 16 (O) Antiseptic type atmosphere of earth = 46

         = 46 – 10 (H8) = 36 

         = 36 = C3 = Carbon 

 

 

Antiseptic type atmosphere into the hospitals,     

 

Chemical formula from 0.62 hours = CH3CH2CH2OH

                                 = CH3CH2CH2OH, 1-propanol 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                      = 4166666.66 / 24 hour = 173611.11

                      = 173611.11 / 60 minute = 2893.51

                      = 2893.51 / 46.669 (COOH + H = 46.5) = 62

                      = 62 = CH3CH2CH2OH = (E = m2c), 

 

 

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