Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

Jun 1st 2017, 11:50 am
Posted by aqeelsika
569 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Acetaldehyde 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 45% * H0.01 of fusion = 0.45 hour 

 

                       Because 

                       Hour = 0.45 * 19 proton of K = 8.55-Fluorine   

                            = 8.55 – 6 proton of C = 2.55-Hydrogen 

 

Fluorine = 9 proton   

Hydrogen = 2.5 proton 

 

Carbon = 8.55 * 2.55 = 21.8025

       = 21.8025 + 23.1975 (CH3 + H6 = 23.25) = 45

       = 45

 

Chemical = 45 – 16 (O) home kitchen type atmosphere of earth = 29

         = 29 – 5 (H4) = 24 

         = 24 = C2 = Carbon 

 

 

home kitchen type atmosphere such as acetic acid found in each kitchen of world, 

 

Chemical formula from 0.45 hours = CH3CHO

                                 = CH3CHO, Acetaldehyde 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                          = 4166666.66 / 24 hour = 173611.11

                          = 173611.11 / 60 minute = 2893.51

                          = 2893.51 / 64.300 (OH)3 + C = 63.75) = 45

                          = 45 = CH3CHO = (E = m2c), 

 

Bookmark & Share:

Please Like Us
Please Like Us