Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

May 24th 2017, 11:06 am
Posted by aqeelsika
492 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Formaldehyde 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 30.5% * H0.01 of fusion = 0.305 hour 

 

                       Because 

                       Hour = 0.305 * 30 proton of Zn = 9.15-Fluorine   

                            = 9.15 – 6 proton of C = 3.15-Lithium 

 

Fluorine = 9 proton   

Lithium = 3 proton 

 

Carbon = 9.15 * 3.15 = 28.8225

       = 28.8225 + 1.6775 (H + 0.4275 = 1.6775) = 30.5

       = 30.5

 

Chemical = 30.5 – 16 (O) Oxidation of methanol atmosphere of earth = 14.5

         = 14.5 – 2.5 (H2) = 12   

         = 12 = C = Carbon   

 

 

Chemical formula from 0.305 hours = CH2O

                                  = CH2O, Formaldehyde 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                          = 4166666.66 / 24 hour = 173611.11

                          = 173611.11 / 60 minute = 2893.51

                          = 2893.51 / 94.8691 (H2O2)2 + CH + C = 94.25) = 30.5

                          = 30.5 = CH2O = E = m2c,          

 

 

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