Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

May 23rd 2017, 11:14 am
Posted by aqeelsika
496 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Dichloromethane 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 84.5% * H0.01 of fusion = 0.845 hour 

 

                       Because 

                       Hour = 0.845 * 13 proton of Al = 10.985-Sodium   

                            = 10.985 – 6 proton of C = 4.985-Boron 

 

Sodium = 11 proton   

Boron = 5 proton 

 

Carbon = 10.985 * 4.985 = 54.760225

       = 54.760225 + 29.739775 (CH4 + C = 29) = 84.5

       = 84.5

 

Chemical = 84.5 – 70 (Cl2) A Make-up remover atmosphere of earth = 14.5

         = 14.5 – 2.5 (H2) = 12   

         = 12 = C = Carbon   

 

 

Chemical formula from 0.845 hours = CH2Cl2

                                  = CH2Cl2, Dichloromethane 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                          = 4166666.66 / 24 hour = 173611.11

                          = 173611.11 / 60 minute = 2893.51

                          = 2893.51 / 34.242 (H2O2 = 34.5) = 84.5

                          = 84.5 = CH2Cl2 = E = m2c,         

 

 

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