Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

May 18th 2017, 11:35 am
Posted by aqeelsika
518 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

1,3-Butadiene 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 55.5% * H0.01 of fusion = 0.555 hour 

 

                       Because 

                       Hour = 0.555 * 16 proton of S = 8.88-Fluorine   

                            = 8.88 – 6 proton of C = 2.88-Lithium 

 

Fluorine = 9 proton   

Lithium = 3 proton 

 

    Carbon = 8.88 * 2.88 = 8.9776

          = 25.5744 + 29.9256 (CO + H1 = 29.25) = 55.5

          = 55.5

 

Chemical = 55.5 – 7.5 (H6) Synthetic rubber type atmosphere of earth = 48

         = 48 = C4 = Carbon   

 

Chemical formula from 0.555 hours = CH2CHCHCH2

                                  = CH2CHCHCH2, 1,3-Butadiene 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                          = 4166666.66 / 24 hour = 173611.11

                          = 173611.11 / 60 minute = 2893.51

                          = 2893.51 / 52.135 (CO + H2O + H3 + 51.5) = 51.5) = 55.5

                          = 55.5 = CH2CHCHCH2 = E = m2c,         

 

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