Sikander Aqeel

ATMOSPHERE OF CARBON ON EARTH

May 17th 2017, 11:31 am
Posted by aqeelsika
503 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Formate ion 

        Carbon = 12.0107-C  

        Carbon = 12.0107 

        Carbon = 6 proton 

        Carbon = 6 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (6)           +     b2 (6)   

 

        a2 (36)          + b2 (36) = c2

 

        a2 + b2 = 72 = c2 

        a2 + b2 = 72 / 12.0107-C = 5.99

        a2 + b2 = 5.99 

        Carbon proton = 6 - 5.99 + H0.01

 

 

Carbon energy atmosphere = 45.25% * H0.01 of fusion = 0.4525 hour 

 

                       Because 

                       Hour = 0.4525 * 16 proton of S = 7.24-Nitrogen   

                            = 7.24 – 6 proton of C = 1.24-Hydrogen

 

Nitrogen = 7 proton   

Hydrogen = 1.25 proton 

 

    Carbon = 7.24 * 1.24 = 8.9776

          = 8.9776 + 36.2724 (OH + H20 = 35.75) = 45.25 

          = 45.25

 

Chemical = 45.25 – 32 (O2) A ion type atmosphere of earth = 13.25

         = 13.25 – 1.25 (H) = 12 

         = 12 = C = Carbon   

 

Chemical formula from 0.4525 hours = CHO2-

                                   = CHO2-, Formate ion 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 72 (m2) = 4166666.66

                          = 4166666.66 / 24 hour = 173611.11

                          = 173611.11 / 60 minute = 2893.51

                          = 2893.51 / 63.944 (CH2OH)2 = 63.5) = 45.25

                          = 45.25 = CHO2- = E = m2c,         

 

 

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