NEAREST HUNDRED-AND-TWELVE ORBIT OF SUN:

Sun’s Hundred-and-Twelve orbit, which is after the Mars for Jupiter. This orbit is One Hundred-and-Twelve minute far from sun. And One Hundred-and-Twelve minute are equal to 6720 seconds. So 6720 x 300000000 = 2016000000000 meters distance from sun. And to the know days 2016000000000 / 24 hour / 60 minute / 1000000 light measure = 1400 days distance of Hundred-and-Twelve orbit from the sun. Now to the orbit 2016000000000 x 6 radius = 12096000000000 meter orbit. To the know days 12096000000000 / 24 hours / 360 degree / 1000000 light measurement = 1400 days of yearly rotation for Hundred-and-Twelve minute away orbit of the sun.   

Here is not present any satellite.

But I am doing solve value of each orbit. Even which orbit is away from the sun? So it is Hundred-and-Twelve orbit of sun. If in future you made a humans colony into space. Then you can acquire the energy from even any orbit of sun. 

Outer equator of Satellite: 

So orbital radius or distance is 6720 light seconds between Orbit and sun. Now for get the outer equator in km, if any satellite happens there, So 6720 x 21.78 code of diameter = 146361.6 kilometers outer equator of the satellite. And by radius that 146361.6 / 6 radius = 24393.6 kilometers radius. 

Earth radius is 6359.76 Kilometers

And by earth the radius of satellite is 18033.84 kilometer large. Because much distance contains on large radius, but the Jupiter is large than our Earth, because Jupiter not separated alone from the sun in beginning, that the mars was attached with the earth. And some time later, the Mars again separated from the earth. From this reason, Mars’s size is small from our earth. So the Mars was separated two times in own life. Such as` first times separated from the sun with Earth, and second times from the earth to live alone, Now satellite total seconds are 6720 x 3.63 kg length weight code = 24393.6 / 17.424 Code of days = 1400 days of Hundred-and-Twelve orbit of satellite.          

Outer equator of Jupiter: 

The outer equator find out of Jupiter from the distance of sun is very easy. Because the Jupiter comes in existence alone, therefore we find out the outer circle of Jupiter, Such as Jupiter days are 4337.5 around the sun. And for outer circle in kilometers 4337.5 days x 3 angle of triangle x 1.6 value of angle = 20820 seconds distance of Jupiter from sun. So 20820 x 21.78 Code of outer equator = 453459.6 kilometers outer equator of Jupiter.     

Temperature of Jupiter:  

So we shall use light seconds distance for the temperature of Jupiter, the light speed is 300000000 m/s / 20820 = 14409.22190201729106628242074928 / 24 hours = 600.38424591738712776176753121998 / 60 minute = 10.0064 Centigrade temperature of Jupiter. And Jupiter is 347 minute away from the Sun. 

So radius of orbit is 6720 light seconds. Then 300000000 / 6720 seconds = 44642.857142857142857142857142857 / 24 = 1860.119047619047619047619047619 / 60 = 31.001984126984126984126984126984 Centigrade temperature will happen of satellite or the Hundred-and-Twelve orbit, and it is right and perfect temperature. Because when we shall divide with Venus temperature with the satellite or for the temperature of orbit, then our proof will be strong. So satellite temperature is 31.001984126984126984126984126984 / 10.0064 = 3.098 x 112 minute = 346.976 + -0.024 = 347 minute distance of Jupiter from the sun. Here we shall say. If you have basic Math would have to be right. Then you can solve each matter of universe. Now we have 31.00 Centigrade temperature to the satellite or of the orbit. If you are thinking that it is too much temperature, then you are wrong. Because which Math I am going to tell you, that our problem will be solved about space,  

Earth temperature: 

/ 1752 seconds distance = 171232.8767 / 24 hours = 7134.703196 / 60 minute = 118.91 temperature of earth. So water temperature 59.455 - 118.91 = 59.455 Centigrade temperature of earth. 

The velocity of satellite in own orbit: 

The satellite’s velocity will happen 8.63 kilometers per seconds in own orbit. And it velocity is 5 percent excessive from the sun diameter. So it is finally accurate law of velocity. Now to the make law we shall use the sun diameter and atom two conditions. So satellite days are 1400 in own orbit. Next 1.25 is warm condition of Hydrogen atom and 1.25 is cool condition of Hydrogen. After collect of both, 1.25 + 1.25 = 2.5. Law of velocity now satellite total days are 1400 / 2.5 = 560 and it is the code of speed; the sun diameter is 4833.26 days kilometers. So 4833.26 / 560 speed code = 8.63 kilometers per seconds speed of satellite. I had explained about velocity of planet four years ago. Which was sixth percent accurate, and it law is hundred percent accurate. Actually! I am explaining about many subjects in same time. So can be mistake but I itself shall do accurate own each mistake. And in the beginning the Internet and English were new things for my. 

Velocity of Jupiter: 

The Jupiter days are 4337.5 / 2.5 = 1735 and sun outer equator is 4833.26 / 1735 = 2.78 kilometers per seconds’ velocity of Jupiter around the sun. 

Velocity of Earth: 

The Earth days are 365 / 2.5 = 146 and sun outer equator is 4833.26 / 146 = 33.11 kilometers per seconds’ velocity of Earth around the sun.   

The size of sun from One Hundred-and-Twelve minute distance: 

It is also very important situation. You always see the sun in 1.5 feet size from the earth. But if you want imagine size of sun from One Hundred-and-Twelve minute away. Then this law will help us. Many events rise up into the Universe. Sometimes a star suddenly very quickly melts to be small size. Fact about a star which was against across of our solar system in the milky-way, And around this star the life were present in two planets. There in only four centuries. Their star was fifty percent melt. From this reason there life was suddenly finished into the two planets. Why it happened, actually you do not know about the Star Quake which happens very dangerous. Tell later to which details. So we are doing probe orbit of sun. From Hundred-and-Twelve minute away, so from One Hundred-and-Twelve minute away the sun size will happen 7 Inch. Now by Math that the sun Outer circles is 4833.26 days kilometers. So 4833.26 / 6720 seconds = 0.71923511904761904761904761904762 and we shall only use 0.7 here. So 0.7 x 10 atom = 7 inch size of sun from on One Hundred-and-Twelve minute away. 

Why Jupiter day contains 48 hours. 

What is the value of 60 minute by hours? 

So we should know that what is the value of 60 minute and why one day of Jupiter is equal to 48 hours, or what is the value of one minute into the universe, or 60 minute is only a way for find the hours. But we need an axis rotation of planet into the hours. 

Law of Axis rotation, 

Actually the matter of axis rotation belongs with time and Super Code of rotation. So we shall find the Super Code for solve of axis rotation. So Earth rotation Code is 1.2,, Mars rotation Code is 1.1,, Jupiter rotation Code is 3.85,, Saturn rotation Code is 5.375,, Uranus rotation Code is 4.91,, Neptune rotation code is 3.34,, and Pluto rotation Code is 2.41, ( and 60 minute are basic limit of one hour ) 

Axis rotation and 4337.5 days of Jupiter:  

So Jupiter distance is 20820 light seconds from the sun. Then 20820 / 3.85 Code = 5407.7922077922077922077922077922 / 60 = 90.12 hours. So the 90.12 hours are value of axis rotation for complete one day of Jupiter. 

Axis rotation and 365 days of Earth: 

Now one Proton containing on five photon and proton is electrical active substance into the space. So Axis rotation = one Proton and one Proton = five photon. And if the zero minute is a distance of planet, then we shall write 0 - 5 = 5 Axis rotation of planet. If the 1 minute is distance of planet, then we shall write 1 - 5 = 4 Axis rotation of planet. 

Axis rotation of satellite: 

So 112 minute distance of satellite, then 112 / 93.33 hours for time Code = 1.2, So 6720 light seconds distance of satellite then 6720 / 1.2 = 5600 / 60s = 93.33 hours, or satellite Axis rotation would be 93.33 hours per day. And this Axis rotation is nearly too much from the Earth rotation. 

Axis rotation of Jupiter: 

So 347 minute distance of Jupiter, then 347 / 90 hours is time Code = 3.8555555555555555555555555555556, and 20820 light seconds distance of Jupiter from sun. And Jupiter Code is 3.8555555555555555555555555555556. Then 20820 / 3.8555555555555555555555555555556 = 5400.0000000000000000000000000008 / 60 = 90.00, hour, or Jupiter rotation would be 90 hour per day. And this rotation is too much from the Earth rotation. 

Speed of planet, and axis rotation: 

Jupiter speed code is 1735, because 4337.5 days / 2.5 two hydrogen atom = 1735, so it is a code of Jupiter speed. Now for know the speed in kilometers. We use the Outer circle of sun. 4833.26 / 1735 = 2.785 kilometer speed of Jupiter around the sun. So 1735 is the code of speed. Now for know the axis rotation we shall use the 274.4 code and radius law 6. So 1735 / 6 = 289.166666666667 / 3.21 angle = 90 hours axis rotation of Jupiter.  

Speed code of satellite and axis rotation: 

Now 560 is a code of satellite speed, and 6 is a law of radius. So 560 / 6 radius = 93.33 or 93.33 hours axis rotation of satellite. 

As a proof by new energy law with Jupiter: 

The rotation Code is first important subject, and Mars rotation Code is 4337.5. So for know the rotation of Jupiter. We shall use the Code with New energy law. So energy law is E = m + m = C1. Then E= m347 minute + m347 minute = 694 x 300000000 = 208200000000 / 4337.5 days of Jupiter = 48000000 / 1000000 light measurement = 48 hours axis rotation of Mars or rotation value of orbit of Mars. 

So axis rotation law is: 

Days / 5 photon of one proton = Code. And Code / 4.8 one neutron energy = axis rotation of one hours x 24 hours = days of earth. 

As a test with satellite: 

So satellite days are 1400 / 5 = 280 Code of satellite. So 280 / 4.8 = 58.333333333333333333333333333333 x 24 hours axis rotation of satellite = 1400 days of Satellite. And 93.33 hours axis rotation of satellite,   

As a proof by 360 degree: 

Now we have 360 degrees of any circle and these 360 degrees belongs with a pair, like one day of 24 hours, and a night of 24 hours, or 24 up degree, and 24 down degrees. Or 0 to 180 degrees equal to day, or up side. And 180 to 0 equal to night or down side. But the value of same of both So by the axis rotation 24 hours are equal to one day. And 24 hours are equal to one night. But you do the count the day of 12 hours, and night of 12 hours. Actually yours dating system is wrong. 

Now about 1400 days of satellite and Axis rotation: 

1400 / 360 degree = 3.8888888888888888888888888888889 x 24 part of first pair = 93.33 and 93.33 is a axis rotation of satellite. 

Now about 365 days of Earth and Axis rotation: 

365 / 360 degree = 1.0138888888888888888888888888889 x 24 part of first pair = 24.33 and 24.33 hour is an axis rotation of Earth. 

Now about 4337.5 days of Jupiter: 

4337.5 / 360 = 12.048611111111111111111111111111 x 24 part of first pair = 289.16666666666666666666666666667 and it is axis rotation. So 289.16666666666666666666666666667 x 24 part of second pair = 6940 / 1.6 = 4337.5 days of the orbit of Jupiter. 

Second proof by Jupiter: 

4337.5 / 360 = 12.048611111111111111111111111111 x 24 hours = 289.16666666666666666666666666667 x 4.8 one neutron energy = 1388 / 4 photon of one neutron = 347 minute distance of Jupiter from the sun. And it is a relation between the axis rotation and the distance of earth. 

Axis rotation of Jupiter:

The Earth days are containing on 15.20 ratios. And the Jupiter days are 15.42 ratios. Because 365 / 24 hours = 15.20, although the Jupiter orbit is too large from earth, but by ratio the Jupiter keeps 15.42 value of Axis rotation. Because Jupiter days are 4337.5 / 360 = 12.048611111111111111111111111111 x 24 hours = 289.16666666666666666666666666667 x 4.8 one neutron energy = 1388 / 15.42 ratio = 90.01 hours Axis rotation of Jupiter.     

Second proof by Earth: 

365 / 360 = 1.013888888889 x 24 hours = 24.33333333333 Axis rotation x 4.8 one neutron energy = 116.8 / 4 photon of one neutron = 29.2 minute distance of earth from the sun. And it is a relation between the axis rotation and the distance of earth. 

Now about 1400 days of satellite: 

1400 / 360 = 3.8888888888888888888888888888889 x 24 hours = 93.333333333333333333333333333333 hours Axis rotation x 4.8 one neutron energy = 448 / 4 photon of neutron = 112 minute distance of satellite from the sun. So this law will be called the measurement of distance through the minute. 

Now about 4337.5 days of Jupiter: 

4337.5 / 360 = 12.048611111111111111111111111111 x 24 hours = 289.16666666666666666666666666667 hours new second Axis rotation x 4.8 one neutron energy = 1388 / 4 photon of neutron = 347 minute distance of Jupiter from the sun. So this law will be called the measurement of distance through the minute. 

Real Axis Rotation of Jupiter

So 289.16 or 290 hours is new without moon axis rotation of Jupiter but as we include gravitation of all 16 moon of Jupiter then the axis rotation will be automatically less because by the Jupiter being used energy for move continuous of moon which ratio is 5.625 photon of Proton. So for real axis rotation of Jupiter we shall use total moon and ratio of photons of sun. So Total moon are 16 x 5.625 = 90 axis rotation of Jupiter so why Jupiter axis rotation is very less because the Jupiter is very large planet with 16 moon, and from this reason Jupiter axis rotation is 90 hours per day, So the Jupiter axis rotation value is 15.42, and we have 1388 total neutron energy. And from this reason 1388 / 15.42 = 90.01 Axis rotation of Jupiter,     

Gravitation of Satellite: 

The gravitation is a part of radius of mass, and distance is not affect on gravitation of Satellite. or Mercury is very close to sun. And this distance is not doing affect on gravitation of Mercury. or Pluto is too far from sun. And Pluto gravitation is ratio of radius of Pluto. So mass weight is zero into the space. Because the space have itself unlimited weight and this unlimited weight of space is doing zero weight of mass. But the radius of mass, which is a power for outer surface of mass If the radius is large then the outer circle would also large of mass. Or 6359.76 kilometer is radius of earth. Then 6359.76 kilometer outer space of earth is in control of gravitation of earth. And from this reason, people cannot easily go in space. So the gravitation is a heap of particle. If the heap of particle is too large then gravitation would also too much, 

So the distance belongs with radius of planet, and the radius belongs with Gravitation of planet. Now we are using law of King Gravitation for find out radius of satellite. Actually we should know many law of any one system. If we are in journey and our one system has been damaged, then we can use other system for continuous journey. 

Gravitation Law of King S: 

The earth keeps 10.89 falling gravitation, or “g” = 10.89. And the against Gravitation is 9.6, or “hg” = 9.6, and we shall multiply of each other for stand up gravitation law of king, so 10.89 x 9.6 = 104.544 

Gravitation law of king: 

So the Gravitation Law of King-S is 104.544 x 1400 days of satellite = 146361.6 kilometers outer equator of satellite. Now for radius 146361.6 / 6 = 24393.6 km radius of satellite and it will be called the natural radius and outer equator, because we are doing measurement from surface of sun.

LAW OF AGAINST GRAVITATION OF SATELLITE:

So what would be gravitation or value of “hg” at the satellite? That we are doing solve this gravitation through the Math. So the satellite outer equator is 146361.6 kilometer, and radius is 24393.6 kilometers, and 36.816 m/s “hg” of satellite. or 36.816 m/s is a against gravitation or “hg” of satellite. Because satellite outer equator is 146361.6 km / 10.89 earth “g” = 13440 / 1400 days of satellite = 9.6, It was first step of gravitation. So satellite radius is 24393.6 / 6359.76 radius of earth = 3.835-Sa and it was second step of gravitation. So after multiply of both, 9.6 x 3.835-Sa = 36.816 against gravitation of satellite. and this satellite gravitation is attached with gravitation of earth. So 36.816 meter per seconds against gravitation of satellite, which is 112 minute away from sun 

LAW OF FALLING GRAVITATION OF SATELLITE:

So what would be gravitation or value of “g” at the satellite? That we are doing solve this gravitation through the Math. So the satellite outer equator is 146361.6 kilometer, and radius is 24393.6 kilometers, and 41.76315 m/s “g” of satellite. or 41.76315 m/s is a falling gravitation or “g” of satellite. Because satellite outer equator is 146361.6 km / 9.6 earth “hg” = 15246 / 1400 days of satellite = 10.89, It was first step of gravitation. So satellite radius is 24393.6 / 6359.76 radius of earth = 3.835-Sa and it was second step of gravitation. So after multiply of both, 10.89 x 3.835-Sa = 41.76315 falling gravitation of satellite. And this satellite gravitation is attached with gravitation of earth. So 41.76315 meter per seconds falling gravitation of satellite (or “g”) which is 112 minute away from sun? 

FIRST PROOF FOR EQUATOR OF SATELLITE:   

Then 36.816 “hg” x 10.89 “g” = 400.92624 x 1400 days of satellite = 561296.736 km / 3.835-Sa = 146361.6 km outer equator of satellite, 

SECOND PROOF FOR EQUATOR OF EARTH:   

Then 41.76315 “g” x 9.6 “hg” = 400.92624 x 365 days of Earth = 146338.0776 km / 3.835-Sa = 38158.56 km outer equator of Earth, 

BY YOUR LAW EQUATOR OF JUPITER, 

Then 41.76315 “g” x 9.8 “g” = 400.92624 x 4337.5 days of Jupiter = 1739017.566 km / 3.835-Sa = 453459.6 km outer equator of Jupiter,   

THIRD PROOF FOR EQUATOR OF MERCURY:   

Then 36.816 “hg” x 10.89 “g” = 400.92624 x 86.26 days of Mercury = 34583.8974624 km / 3.835-Sa = 9017.96544 km outer equator of Mercury, 

FOURTH PROOF FOR EQUATOR OF VENUS:   

Then 41.76315 “g” x 9.6 “hg” = 400.92624 x 223.75 days of Venus = 89707.2462 km / 3.835-Sa = 23391.72 km outer equator of Venus, 

BY YOUR LAW EQUATOR OF EARTH, 

Then 36.816 “hg” x 9.8 “hg” = 360.7968 x 365 days of Earth = 131690.832 km / 3.835-Sa = 34339.2 km outer equator of Earth, 

So by your law 9.8 “g” and 9.8 “hg” is value of unbalance. Because the equator happening small from value of 9.8 “g”. And other equator happening large from 9.8 “hg”, Here if size happening large of planet, the both gravitation are also happening large continuous!