GRAVITATION LAW FOR DEIMOS MOON OF MARS:

The Deimos! Which is an abnormal moon of Mars, because the distance containing on mass, if the distance is long then mass will be large, but here mass is very less than the distance, And from this reason we shall use nearly less from half year. Such Deimos days of rotation are 1.26 around of mars, but the Deimos mass is very less than distance. And from this reason, we shall use 0.40 days for find out outer equator of Deimos by real size, 

THE SECRET LAW OF DEIMOS, 

(1) The earth yearly days are 365 * 14.4 charge of a electron = 5256 km distance of earth, because 5256 km / 24 hours / 60 minute = 3.65 * 100 cm = 365 yearly days of earth. 

(2) The Deimos yearly days are 1.26 * 14.4 charge of one electron = 18.144 * 1000 meter = 18144 km distance of Deimos from Mars, Now 18144 km / 24 hours / 60 minute = 12.6 / 10 cm = 1.26 yearly days of Deimos, now for outer equator of deimos, we shall do less of year, such 1.26 / 2 per-cent = 0.63 days of half year, then 0.63 – 0.23 average speed = 0.40 days for size of Deimos in km, 

DETAILS OF DEIMOS, 

Distance is 18144 km from Mars, 1.26 days of year, Radius 6.9696 km, Outer equator 41.8176 km, Diameter 13.9392 km, and the deimos size is contain on 0.40 days. And deimos is 6.048 light seconds away from mars. Because 6.048 / 4.8 energy of neutron = 1.26 yearly days of Deimos.   

LAW IN KILOMETERS OF DEIMOS:

Gravitation law of King-S is 104.544 * 0.40 day size of Deimos = 41.8176 kilometers outer equator of Deimos. So 41.8176 / 6 radius = 6.9696 kilometers radius of Deimos,               

LAW OF AGAINST GRAVITATION OF DEIMOS. 

So what would be gravitation or value of “hg” at the Deimos. That we are doing solve this gravitation through the Math. So the Deimos outer equator is 41.8176 kilometer, and radius is 6.9696 kilometers, and 0.010464 m/s “hg” of Deimos. or 0.010464 m/s is against gravitation or “hg” of Deimos. Because Deimos outer equator is 41.8176 km / 10.89 earth “g” = 3.84 / 0.40 day size of Deimos = 9.6 It was first step of gravitation. So Deimos radius is 6.9696 km / 6359.76 radius of earth = 0.00109-Sa and it was second step of gravitation. So after multiply of both, 9.6 * 0.00109-Sa = 0.010464 m/s against gravitation of Deimos. And this Deimos “gh” gravitation is attached with gravitation of Earth. So 0.010464 meter per seconds against gravitation of Deimos, which is 6.048 light seconds away from Mars, 

1Th PROOF FOR EQUATOR OF DEIMOS: 

Then 0.010464 “hg” * 10.89 “g” = 0.11395296 * 0.40 days size of Deimos = 0.045581184 km / 0.00109-Sa = 41.8176 km outer equator of Deimos,     

2Th PROOF FOR EQUATOR OF EARTH: 

Then 0.010464 “hg” * 10.89 “g” = 0.11395296 * 365 days size of Earth = 41.5928304 km / 0.00109-Sa = 38158.56 km outer equator of earth, 

3Th PROOF FOR EQUATOR OF SUN: 

Then 0.010464 “hg” * 10.89 “g” = 0.11395296 * 399443296.60 days of sun = 45517745.999727936 km / 0.00109-Sa = 41759399999.7504 km outer equator of sun, because 41759399999.7504 / 6 radius = 6959899999.9584 + 0.0416 = 6959900000 radius of sun.  

4Th PROOF BY YOUR LAW EQUATOR OF DEIMOS: 

Then 0.010464 “hg” * 9.8 = 0.1025472 * 0.40 days size of Deimos = 0.04101888 km / 0.00109-Sa = 37.632 km outer equator of Deimos, 

LAW OF FALLING GRAVITATION OF DEIMOS: 

So what would be gravitation or value of “g” at the Deimos. That we are doing solve this gravitation through the Math. So the Deimos outer equator is 41.8176 kilometer, and radius is 6.9696 kilometers, and “g” is 0.0118701 m/s of Deimos. Or 0.0118701 m/s is a falling gravitation or “g” of Deimos Because Deimos outer equator is 41.8176 km / 9.6 earth “hg” = 4.356 / 0.40 days size of Deimos = 10.89, It was first step of gravitation. So Deimos radius is 6.9696 / 6359.76 radius of earth = 0.00109-Sa and it was second step of gravitation. So after multiply of both, 10.89 * 0.00109-Sa = 0.0118701 m/s falling gravitation of Deimos. And this Deimos “g” gravitation is attached with gravitation of earth. So 0.0118701 meter per seconds falling gravitation of Deimos or “g” and which is 6.048 light seconds away from Mars,

5th PROOF FOR EQUATOR OF DEIMOS: 

Then 0.0118701 “g” * 9.6 “hg” = 0.11395296 * 0.40 days size of Deimos = 0.045581184 km / 0.00109-Sa = 41.8176 km outer equator of Deimos, 

6Th PROOF FOR EQUATOR OF EARTH: 

Then 0.0118701 “g” * 9.6 “hg” = 0.11395296 * 365 days of Earth = 41.5928304 km / 0.00109-Sa = 38158.56 km outer equator of earth, 

7Th PROOF FOR EQUATOR OF SUN: 

Then 0.0118701 “g” * 9.6 “hg” = 0.11395296 * 399443296.60 days of Sun = 45517745.999727936 / 0.00109-Sa = 41759399999.7504 km outer equator of Sun, because 41759399999.7504 / 6 radius = 6959899999.9584 + 0.0416 = 6959900000 radius of Sun.  

8Th PROOF BY YOUR LAW EQUATOR OF EARTH, 

Then 0.0118701 “g” * 9.8 = 0.11632698 * 365 days size of Earth = 42.4593477 km / 0.00109-Sa = 38953.53 km outer equator of Earth, so by your law the Earth is 794.97 km large than my measurement of Earth.

So the Deimos “hg” = 0.010464 meter per second, and the “g” = 0.0118701 meter per second. And 0.00109-Sa is a code of both gravitation, and the gravitation is main function of universe. And all system of universe is contains on gravitation of particle. And you all are very different from each other by face and body. Your gravitation of cells is very different from each other. And it is a long chapter about genetic gravitation. Which will be started in 2017, (1000 / 10.89 = 91.82!! 1000 / 1.9602 = 510.15 / 91.82 = 5.55!! 1000 / 5.55, 180.18),