Space and Gravitation Law of Planets and Stars!

GRAVITATION LAW FOR PHOBOS MOON OF MARS: 

Gravitation law of King-S is 104.544 x 0.60416 day size of Phobos = 63.16 kilometers outer equator of Phobos. So 63.16 / 6 radius = 10.52 kilometers radius of Phobos.  

The Phobos distance is 8699.904 km away from surface of Mars, and distance can be converted in day Through the seconds, or earth is away 5256 km away, but for million km 5256 x 100000 = 525600000 / 24 hours / 60 minute / 1000 meter of km = 365 days of earth, therefore 5256 km / 24 / 60 = 3.65 * 100 cm = 365 days of earth, but the Phobos is only km away from Mars. Then 8699.904 / 24 hours / 60 = 6.0416 / 10cm = 0.60416 percent day of year Phobos, because the Phobos is 604.14 per-cent small moon than the earth. Or 365 days / 0.60416 = 604.14, now Phobos = 63.16 km x 604.14 = 38157.4824 km outer equator of earth.          

LAW OF AGAINST GRAVITATION OF PHOBOS. 

So what would be gravitation or value of “hg” at the Phobos. That we are doing solve this gravitation through the Math. So the Phobos outer equator is 63.16 kilometer, and radius is 10.52 kilometers, and 0.01584 m/s “hg” of Phobos. or 0.01584 m/s is against gravitation or “hg” of Phobos. Because Phobos outer equator is 63.16 km / 10.89 earth “g” = 5.799816 / 0.60416 day size of Phobos = 9.6 It was first step of gravitation. So Phobos radius is 10.52 km / 6359.76 radius of earth = 0.00165-Sa and it was second step of gravitation. So after multiply of both, 9.6 x 0.00165-Sa = 0.01584 m/s against gravitation of Phobos. And this Phobos “gh” gravitation is attached with gravitation of Earth. So 0.01584 meter per seconds against gravitation of Phobos, which 8699.904 km away from Mars, 

1Th PROOF FOR EQUATOR OF PHOBOS: 

Then 0.01584 “hg” x 10.89 “g” = 0.1724976 x 0.60416 days size of Phobos = 0.104216150016 km / 0.00165-Sa = 63.16 km outer equator of Phobos,     

2Th PROOF FOR EQUATOR OF EARTH: 

Then 0.01584 “hg” x 10.89 “g” = 0.1724976 x 365 days size of Earth = 62.961624 km / 0.00165-Sa = 38158.56 km outer equator of earth, 

3Th PROOF FOR EQUATOR OF SUN: 

Then 0.01584 “hg” x 10.89 “g” = 0.1724976 x 399443296.60 days of sun = 68903009.99958816 km / 0.00165-Sa = 41759399999.7504 km outer equator of sun, because 41759399999.7504 / 6 radius = 6959899999.9584 + 0.0416 = 6959900000 radius of sun.  

4Th PROOF BY YOUR LAW EQUATOR OF PHOBOS: 

Then 0.01584 “hg” x 9.8 = 0.155232 x 0.60416 days size of Phobos = 0.09378496512 km / 0.00165-Sa = 56.8393728 km outer equator of Phobos, 

LAW OF FALLING GRAVITATION OF PHOBOS: 

So what would be gravitation or value of “g” at the Phobos. That we are doing solve this gravitation through the Math. So the Phobos outer equator is 63.16 kilometer, and radius is 10.52 kilometers, and “g” is 0.0179685 m/s of Phobos. Or 0.0179685 m/s is a falling gravitation or “g” of Phobos Because Phobos outer equator is 63.16 km / 9.6 earth “hg” = 6.5791666 / 0.60416  days size of Phobos = 10.89, It was first step of gravitation. So Phobos radius is 10.52 / 6359.76 radius of earth = 0.00165-Sa and it was second step of gravitation. So after multiply of both, 10.89 x 0.00165-Sa = 0.0179685 m/s falling gravitation of Phobos. And this Phobos “g” gravitation is attached with gravitation of earth. So 0.0179685 meter per seconds falling gravitation of Phobos or “g” which 8699.904 km away from Mars,

5th PROOF FOR EQUATOR OF PHOBOS: 

Then 0.0179685 “g” x 9.6 “hg” = 0.1724976 x 0.60416 days size of Phobos = 0.104216150016 km / 0.00165-Sa = 63.16 km outer equator of Phobos, 

6Th PROOF FOR EQUATOR OF EARTH: 

Then 0.0179685 “g” x 9.6 “hg” = 0.1724976 x 365 days of Earth = 62.961624 km / 0.00165-Sa = 38158.56 km outer equator of earth, 

7Th PROOF FOR EQUATOR OF SUN: 

Then 0.0179685 “g” x 9.6 “hg” = 0.1724976 x 399443296.60 days of Sun = 68903009.99958816 / 0.00165-Sa = 41759399999.7504 km outer equator of Sun, because 41759399999.7504 / 6 radius = 6959899999.9584 + 0.0416 = 6959900000 radius of Sun.  

8Th PROOF BY YOUR LAW EQUATOR OF EARTH, 

Then 0.0179685 “g” x 9.8 = 0.1760913 x 365 days size of Earth = 64.2733245 km / 0.00165-Sa = 38953.53 km outer equator of Earth, so by your law the Earth is 794.97 km large than my measurement of Earth.

So the Phobos “hg” = 0.01584 meter per second, and the “g” = 0.0179685 meter per second. And 0.00165-Sa is a code of both gravitation, and the gravitation is main function of universe. And all system of universe is contains on gravitation of particle. And you all are very different from each other by face and body. Your gravitation of cells is very different from each other. And it is a long chapter about genetic gravitation. Which will be started in 2017, (1000 / 10.89 = 91.82!! 1000 / 1.9602 = 510.15 / 91.82 = 5.55!! 1000 / 5.55, 180.18),