Space and Gravitation Law of Planets and Stars!

GRAVITATION LAW FOR THE PLUTO.

Gravitation law of King-S is 104.544 x 66 day size of Pluto = 6899.904 kilometers outer equator of Pluto. So 6899.904 / 6 radius = 1149.984 kilometers radius of Pluto.

LAW OF AGAINST GRAVITATION OF PLUTO.

So what would be gravitation or value of “hg” at the Pluto. That we are doing solve this gravitation through the Math. So the Pluto outer equator is 6899.904 kilometer, and radius is 1149.984 kilometers, and 1.728 m/s “hg” of Pluto. Or 1.728 m/s is a Against gravitation or “hg” of Pluto. Because Pluto outer equator is 6899.904 km / 10.89 earth “g” = 633.6 / 66 day size of Pluto = 9.6 It was first step of gravitation. So Pluto radius is 1149.984 km / 6359.76 radius of earth = 0.180-Sa and it was second step of gravitation. So after multiply of both, 9.6 x 0.180-Sa = 1.728 m/s against gravitation of Pluto. And this Pluto “gh” gravitation is attached with gravitation of Earth. So 1.728 meter per seconds against gravitation of Pluto, which 7237 Minutes away from sun.

1Th PROOF FOR EQUATOR OF PLUTO.

Then 1.728 “hg” x 10.89 “g” = 18.81792 x 66 days size of Pluto = 1241.98272 km / 0.180-Sa = 6899.904 km outer equator of Pluto,    

2Th PROOF FOR EQUATOR OF EARTH.

Then 1.728 “hg” x 10.89 “g” = 18.81792 x 365 days size of Earth = 6868.5408 km / 0.180-Sa = 38158.56 km outer equator of earth,

3Th PROOF FOR EQUATOR OF SUN.

Then 1.728 “hg” x 10.89 “g” = 18.81792 x 399443296.60 days of sun = 7516691999.955072 km / 0.180-Sa = 41759399999.7504 km outer equator of sun, because 41759399999.7504 / 6 radius = 6959899999.9584 + 0.0416 = 6959900000 radius of sun. 

4Th PROOF BY YOUR LAW EQUATOR OF PLUTO,

Then 1.728 “hg” x 9.8 = 16.9344 x 66 days size of Pluto = 1117.6704km / 0.180-Sa = 6209.28 km outer equator of Pluto,

LAW OF FALLING GRAVITATION OF PLUTO.

So what would be gravitation or value of “g” at the Pluto. That we are doing solve this gravitation through the Math. So the Pluto outer equator is 6899.904 kilometer, and radius is 1149.984 kilometers, and “g” is 1.9602 m/s of Pluto. Or 1.9602 m/s is a falling gravitation or “g” of Pluto Because Pluto outer equator is 6899.904 km / 9.6 earth “hg” = 718.74 / 66 days size of Pluto = 10.89, It was first step of gravitation. So Pluto radius is 1149.984 / 6359.76 radius of earth = 0.180-Sa and it was second step of gravitation. So after multiply of both, 10.89 x 0.180-Sa = 1.9602 m/s falling gravitation of Pluto. And this Pluto “g” gravitation is attached with gravitation of earth. So 1.9602 meter per seconds falling gravitation of Pluto or “g”, which is 7237 minutes away from sun.

5th PROOF FOR EQUATOR OF PLUTO.

Then 1.9602 “g” x 9.6 “hg” = 18.81792 x 66 days size of Pluto = 1241.98272 km / 0.180-Sa = 6899.904 km outer equator of Pluto,

6Th PROOF FOR EQUATOR OF EARTH.

Then 1.9602 “g” x 9.6 “hg” = 18.81792 x 365 days of Earth = 6868.5408 km / 0.180-Sa = 38158.56 km outer equator of earth,

7Th PROOF FOR EQUATOR OF SUN.

Then 1.9602 “g” x 9.6 “hg” = 18.81792 x 399443296.60 days of Sun = 7516691999.955072 / 0.180-Sa = 41759399999.7504 km outer equator of Sun, because 41759399999.7504 / 6 radius = 6959899999.9584 + 0.0416 = 6959900000 radius of Sun. 

8Th PROOF BY YOUR LAW EQUATOR OF EARTH,

Then 1.9602 “g” x 9.8 = 19.20996 x 365 days size of Earth = 7011.6354 km / 0.180-Sa = 38953.53 km outer equator of Earth, So by your law the Earth is 794.97 km large than my measurement of Earth.

So the Pluto “hg” = 1.728 meter per second, and the “g” = 1.9602 meter per second. And 0.180-Sa is a code of both gravitation. And the gravitation is main function of universe. And all system of universe is contains on gravitation of particle. And you all are very different from each other by face and body. Your gravitation of cells are very different from each other. And it is a long chapter about genetic gravitation. Which I shall start in 2017. (1000 / 10.89 = 91.82!! 1000 / 1.9602 = 510.15 / 91.82 = 5.55!! 1000 / 5.55, 180.18).