LAST ELECTRON OF TIN WITH CROSS-TRON

WITH ENERGY LAW  ‘‘E = m + m x C1’’

50 last electron of Tin Perhaps for this reason his says atom number 50. Or` atomic number 50 meaning last electron of  Tin So Electron number 50 have also one orbit. and his connect was also with sector 9000L like our earth. and` we 

shall solve motion of last electron with planets motion. we would get here four information. (1) Electron energy. (2) Electron orbit. around the atom (3) micro meter distance between Electron and Tin level till. (4) micro seconds distance 

between Electron and Tin But before the begin. I want some tell you, about Atomic number. with a simple method. Our earth have 365 days, But` if sees to his, like a atomic theory. Then sun is like a atom and Earth is a Electron and his number 

is 365. Perfectly like this` Tin is a atom and his last electron is his atomic number 50 Last electron of Tin that in last Electron revolves around with micro meter speed. after of all.

EARTH HOT AND COLD PERIOD, 

So E = m + m x C1. Earth was hot in begin and Earth has cold now. m365 hot + m365 cold = 730 x C1 300000000 = 2.19000000000 x .008 photon = 1752000000 / 1000m / 100m /10mm = 1752 seconds distance between Earth and Sun. Now` we 

shall make his distance in meters and orbit. 1752 x 300000000 = 525600000000m and` it is distance in meters. 525600000000 x 6 = 3153600000000m and` it is orbit of Earth. Now` to this orbit` we shall do shift in atom number. (1) electron has not 

moon, (2) electron has not days months and year. from this reason` orbit of electron we shall divide with 24 hours and 360 degrees. 3153600000000m / 24 / 360 degrees = 365000000 / 1000m / 100m / 10mm = 365 atomic number. Or` 365 atomic number of Earth. now

TIN LAST  ELECTRON AND, E = m + m x C1. 

Tin atomic number 50. So m50 hot + m50 cold = 100 x C1 300000000 = 30000000000 x .008 one photon = 240000000 / 1000m / 100m /10mm = 240 is micro seconds distance between last electron. and 30000000000 volt energy of last 

electron of Tin Now` we shall make his distance in micro meter 240 x 300000000 =  72000000000 / 1000mc / 100mc /10mc = 72000 it is the distance in micro meters between last electron and  Tin surface till. to the proof 72000 / 24 hours  / 60 minute 

= 50 electron of Tin Now` we shall make to his orbit. 72000 x 6 = 432000 so it is orbit of last electron. in the micro meter measurement. (  now to the atomic number ) we shall make his atomic number. 432000 orbit / 24 hours = 18.000 / 360 degrees = 50 atomic Number of Tin

DETAILS OF ELECTRON OF TIN  

(1) electron energy 30000000000  volt. (2) electron orbit 432000 micro meter. (3)  72000 is micro meter distance between last electron and Tin level till. (4) 240 micro seconds distance between last electron and Tin

PROOF OF DETAILS.  

1. one electron charge 14.4 and one proton charge 25 percent excessive from electron. 

1. 30000000000 volt / 14.4 = 2083333333 x .008 = 17000000 / 1000000 = 16 + 9 = 25  percent excessive charge of proton from one electron.

2. we shall compare between hydrogen size and electron charge. with micro meter distance 72000 

2.   72000 / 1.25 hydrogen size = 56800 / 60 seconds hydrogen time = 960 / 100 area =  9.6 + 4.8 = 14.4 electron charge.

3. orbit, we shall to know percentage of electron charge here. with photon quantity. in one 

proton happens 5 photons. 

3. 432000 / 5 = 86400 / 360 degrees = 240 / 25 proton percentage = 9.6 +  4.8 = 14.4 active charge.  

4. we shall to know percentage of charge with proton charge 28.8. 

4. 240 micro meter distance. So 240 / 28.8 = 8.3 + 4.2 = 12.5 Sun hydrogen atom size  

 LAST ELECTRON OF TIN  AND CROSS-TRON.

If the electron charge value would be right. then will be solved automatically time of mass and weight of mass through the new energy law. So Tin atomic seconds distance 240 

and one electron charge 14.4 and energy law E = m + m x C1. Now, m14.4 + m240 = 254.4 x 300000000 = 76320000000 / 24 hours / 60 minute / 1000m / 100cm light measure = 530 / 189.28  light code = 2.8 Cross-tron of Tin Now to the work condition  Tin will have need 189.28 volt 

energy for one atom and you will be get 30000000000 volt energy from one atom. But how` when we shall be reached at Hydrogen atom till then you will understood. and Every math is possible! If you have right atomic energy law. You know very well that i test at earth first of all. and second at atom. and third at human body.