LAST ELECTRON OF ANTIMONY WITH CROSS-TRON

WITH ENERGY LAW  ‘‘E = m + m x C1’’

Antimony 51 last electron of Antimony Perhaps for this reason his says atom number 51. Or` atomic number 51 meaning last electron of  Antimony So Electron number 51 have also one orbit. and his connect was also with sector 9000L like our earth. and` we 

shall solve motion of last electron with planets motion. we would get here four information. (1) Electron energy. (2) Electron orbit. around the atom (3) micro meter distance between Electron and Antimony level till. (4) micro seconds distance 

between Electron and Antimony But before the begin. I want some tell you, about Atomic number. with a simple method. Our earth have 365 days, But` if sees to his, like a atomic theory. Then sun is like a atom and Earth is a Electron and his number is 365. Perfectly like this` Antimony is a atom and his last electron is his atomic number 51 Last electron of Antimony that in last Electron is turn around with micro meter speed. after of all.

EARTH HOT AND COLD PERIOD, 

So E = m + m x C1. Earth was hot in begin and Earth has cold now. m365 hot + m365 cold = 730 x C1 300000000 = 2.19000000000 x .008 photon = 1752000000 / 1000m / 100m /10mm = 1752 seconds distance between Earth and Sun. Now` we shall make his distance in meters and orbit. 1752 x 300000000 = 525600000000m and` it is distance in meters. 525600000000 x 6 = 3153600000000m and` it is orbit of Earth. Now` to this orbit` we shall do shift in atom number. (1) electron has not 

moon, (2) electron has not days months and year. from this reason` orbit of electron we shall divide with 24 hours and 360 degrees. 3153600000000m / 24 / 360 degrees = 365000000 / 1000m / 100m / 10mm = 365 atomic number. Or` 365 atomic number of Earth. now

ANTIMONY  ELECTRON AND, E = m + m x C1. 

Antimony atomic number 51. So m51 hot + m51 cold = 102 x C1 300000000 = 30600000000 x .008 one photon = 244800000 / 1000m / 100m /10mm = 244.8 is micro seconds distance between last electron. and 30600000000 volt energy of last electron of Antimony Now` we shall make his distance in micro meter 244.8 x 300000000 =  72440000000 / 1000mc / 100mc /10mc = 73440 it is the distance in micro meters between last electron and  Antimony surface till. to the proof 73440 / 24 hours / 60 minute = 51 electron of Antimony Now` we shall make to his orbit. 73440 x 6 = 440640 so it is orbit of last electron. in the micro meter measurement. (  now to the atomic number ) we shall make his atomic number. 440640 orbit / 24 hours = 18.360 / 360 degrees = 51 atomic Number of Antimony

DETAILS OF ELECTRON OF ANTIMONY  

(1) electron energy 30600000000  volt. (2) electron orbit. 440640 micro meter. (3)  73440 is micro meter distance between last electron and Antimony level till. (4) 244.8 micro seconds distance between last electron and Antimony

PROOF OF DETAILS.  

1. one electron charge 14.4 and one proton charge 25 percent excessive from electron. 

1. 30600000000 volt / 14.4 = 2125.000000 x .008 = 17000000 / 1000000 = 17 + 8 = 25 

percent excessive charge of proton from one electron.

2. we shall compare between hydrogen size and electron charge. with micro meter distance 73440 

2.   73440 / 1.25 hydrogen size = 58752 / 60 seconds hydrogen time = 979.2 / 100 area =  9.792 + 4.608 = 14.4 electron charge.

3. orbit, we shall to know percentage of electron charge here. with photon quantity. in one proton happens 5 photons. 

3. 440640 / 5 = 88128 / 360 degrees = 244.8 / 25 proton percentage = 9.792 +  4.608 = 14.4 active charge.  

4. we shall to know percentage of charge with proton charge 28.8. 

4. 244.8 micro meter distance. So 244.8 / 28.8 = 8.5 + 4.0 = 12.5 Sun hydrogen atom size  

 LAST ELECTRON OF ANTIMONY  AND CROSS-TRON.

If the electron charge value would be right. then will be solved automatically time of mass and weight of mass through the new energy law. So Antimony atomic seconds distance 244.8 and one electron charge 14.4 and energy law E = m + m x C1. Now, m14.4 + m244.8 = 259.2 x 300000000 = 77760000000 / 24 hours / 60 minute / 1000m / 100cm light measure = 540 / 207.69  light code = 2.6 Cross-tron of Antimony Now to the work condition  Antimony will have need 207.69 volt 

energy for one atom and you will be get 30600000000 volt energy from one atom. But how` when we shall be reached at Hydrogen atom till then you will understood. and Every math is possible! If you have right atomic energy law. You know very well that i test at earth first of all. and second at atom. and third at human body.