Thickness of Milky-way! Nearly we have total information about the Time Year. which would be enough to do measurement of Milky-way, and we shall do more easy of maths, while the measurement of Milky-way. And it is a important chapter, because 99 percent people cannot use the telescope to look at the universe. but we shall gone on each star through the maths. and our it journey would be too lovely.
1000 Time Year,
is a thickness of Milky-way. now for seconds, that 31356000 x 1000 = 31536000000s thick of Milky-way. and this thickness is nearly three sixty five thousand years. with the light travel 300,000km per seconds or (186,000 miles). Now it how many thickness for imagine, that the Pluto is 5.025 day away from sun. now you can easily imagen about three sixty five thousand years and about 5.025 day distance of Pluto.
So by maths, 31536000000s / 24 hours / 60 minute / 60 seconds = 365000 year thickness of the Milky-way. and the Time Year theory is very easy to understand and imagen. Now you can compare between the Time year and Light year for the success results. Although I shall be won hundred percent, because the Time year theory is totally contain on time, while the Light year is only contain on Light speed, there in no any time into the Light year theory.
Maths of Thickness of Milky-way,
Time Year is 31536000, and Thickness is 1000 Time year distance. Therefore 31536000 x 1000 = 31536000000 seconds distance of Thickness.
Distance in seconds ( 31536000000 / 60 minute / 24 hours / 365 day = 60,000 Seconds ) here 60,000 seconds are equal to one minute.
Distance in Minute ( 31536000000 / 60 seconds / 24 hours / 365 days = 60,000 ) here one hour is equal to 60,000 minute.
Distance in hours ( 31536000000 / 60s / 60m / 365 day = 24,000 ) here 24,000 hours are equal to one day.
Distance in year ( 31536000000 / 60s / 60m / 24 hours = 365,000 year ) and 365,000 are total years of distance of Thickness of Milky-way.
Automation Maths of Time Year,
Actually Time Year maths is a part of automation system. Such as we did solve the distance in time year, Now you want solve distance in the kilometres,
Then 1.44 is a past value of proton`s m** unit. and 365 days are base of Time year. and 60 minute is a unit of time. and here 10mm is a value of seconds, 100cm is value of one minute, and 1000km is a value of one hours.
Milky-way thickness is 3.1536000000s / 365 / 60 minute / 1.44 Proton size = 1000000 / 1000km = 1000Tm. So the Time Year theory is also contain on kilometres.
Measurement in kilometers.
and here 10mm is a value of seconds, 100cm is value of one minute, and 1000km is a value of one hours, and 3 angles are one triangle.
Milky-way thickness is 3.1536000000s x 3 x 10 x 100 1000 = 9.4608000000000000 kilometres thickness of Milky-way. and it is very heavy figures of measurement,
As a proof
9.4608000000000000km / 300,000km light speed / 365d / 24h / 60m /60s / 10mm = 1000Ty thickness of Milky-way. So it is right and best way to do measurement of universe.
So seconds are first step of measurement, and If you will not use first step Then your measurement will not be acceptable. and 31536000Ts is a first step of successful measurement.
As a proof by earth,
earth distance are 1752s x 10 x 100 x 1000 = 1752000000 x 3 angle of triangle = 5256000000 kilometres distance of earth from the sun. So 5256000000 / 300,000km light speed = 17520 / 4.8 Neutron energy = 3650 / 10mm = 365 days of earth
Thickness of Milky-way and date of today.
Milky-way thickness is 3.1536000000s and we shall solve its through the Time year. So 3.1536000000s / 1.491053678 H M** unit = 2.1150144000 / 10512 Code = 2012000 / 1000Ty = 2012 date of today
94000 Time Year is Radius of Milky-way,
The Milky-way radius is 94000 time year. now for seconds, that 31356000 x 94000Ty = 2.964384000000s radius of Milky-way. and this radius is nearly 34310000 years. with the light travel 300,000km per seconds or (186,000 miles). Now it how many thickness for imagine, that the Pluto is 5.025 day away from sun. now you can easily imagen about 34310000 years and 5.025 day distance of Pluto.
So by maths, 2.964384000000s / 24 hours / 60 minute / 60 seconds = 34310000 year Radius of the Milky-way. and the Time Year theory is very easy to understand and imagen. Now you can compare between the Time year and Light year for the success results. Although I shall be won hundred percent, because the Time year theory is totally contain on time, while the Light year is only contain on Light speed, there in no any time into the Light year theory.
Maths of Radius of Milky-way,
Time Year is 31536000, and Radius is 94000 Time year distance. Therefore 31536000 x 94000 = 2.964384000000s seconds distance of Radius.
Distance in seconds ( 2.964384000000s / 60 minute / 24 hours / 365 day = 5,640,000 Seconds ) here 5,640,000 seconds are equal to one minute.
Distance in Minute ( 2.964384000000s / 60 seconds / 24 hours / 365 days = 5,640,000 ) here one hour is equal to 5,640,000 minute.
Distance in hours ( 2.964384000000s / 60s / 60m / 365 day = 2256000 ) here 2256000 hours are equal to one day.
Distance in year ( 2.964384000000s / 60s / 60m / 24 hours = 34310000 year ) and 34310000 are total years distance of Radius of Milky-way.
Automation Maths of Time Year,
Actually Time Year maths is a part of automation system. Such as we did solve the distance in time year, Now you want solve distance in the kilometres,
Then 1.44 is a past value of proton`s m** unit. and 365 days are base of Time year. and 60 minute is a unit of time. and here 10mm is a value of seconds, 100cm is value of one minute, and 1000km is a value of one hours.
Milky-way Radius is 2.964384000000s / 365 / 60 minute / 1.44 Proton size = 94000000 / 1000km = 94000Tm. So the Time Year theory is also contain on kilometres.
Measurement in kilometers.
and here 10mm is a value of seconds, 100cm is value of one minute, and 1000km is a value of one hours, and 3 angles are one triangle.
Milky-way Radius is 2.964384000000s x 3 x 10 x 100 1000 = 8.893152000000000000 kilometres Radius of Milky-way. and it is very heavy figures of measurement,
As a proof
8.893152000000000000km / 300,000km light speed / 365d / 24h / 60m /60s / 10mm = 94000Ty Radius of Milky-way. So it is right and best way to do measurement of universe.
So seconds are first step of measurement, and If you will not use first step Then your measurement will not be acceptable. and 31536000Ts is a first step of successful measurement.
As a proof by Earth,
earth distance are 1752s x 10 x 100 x 1000 = 1752000000 x 3 angle of triangle = 5256000000 kilometres distance of earth from the sun. So 5256000000 / 300,000km light speed = 17520 / 4.8 Neutron energy = 3650 / 10mm = 365 days of earth
Radius of Milky-way and date of today.
Milky-way Radius is 2.964384000000s and we shall solve its through the Time year. So 2.964384000000s / 1.491053678 H M** unit = 1.988113536000 / 10512 Code = 189128000 / 94000Ty = 2012 date of today
Maths of Orbit of Milky-way,
One Time Year seconds are 31536000, and Radius is 94000 Time year distance. Therefore 31536000 x 94000 = 2.964384000000s seconds distance of Radius.
Now for Orbit we shall multiply to radius with six. because six radius are equal to one complete Orbit. So the Milky-way radius is 2.964384000000s x 6 = 1.7786304000000 seconds Orbit of the Milky-way. and here one seconds is equal to 300,000 km. and this figures for imagine, that Earth-Moon is only 144 seconds away from the earth.
Distance in seconds ( 1.7786304000000s / 60 minute / 24 hours / 365 day = 33,840,000 Seconds ) here 33,840,000 seconds are equal to one minute.
Distance in Minute ( 1.7786304000000s / 60 seconds / 24 hours / 365 days = 33,840,000 ) here one hour is equal to 33,840,000 minute.
Distance in hours ( 1.7786304000000s / 60s / 60m / 365 day = 13,536,000 ) here 13,536,000 hours are equal to one day.
Distance in year ( 1.7786304000000s / 60s / 60m / 24 hours = 205,860,000 year ) and 205,860,000 are total year distance of Orbit of Milky-way.
Automation Maths of Time Year,
Actually Time Year maths is a part of automation system. Such as we did solve the distance in time year, Now you want solve distance in the kilometres,
Then 1.44 is a past value of proton`s m** unit. and 365 days are base of Time year. and 60 minute is a unit of time. and here 10mm is a value of seconds, 100cm is value of one minute, and 1000km is a value of one hours.
Milky-way Orbit is 1.7786304000000s / 365 / 60 minute / 1.44 Proton size = 564,000,000 / 1000km = 564000Ty orbit of the Milky-way. So the Time Year theory is also contain on kilometres.
Measurement in kilometers.
and here 10mm is a value of seconds, 100cm is value of one minute, and 1000km is a value of one hours, and 3 angles are to the one triangle.
Milky-way Orbit is 1.7786304000000s x 3 x 10 x 100 1000 = 5.3358912000000000000 kilometres Orbit of Milky-way. and it is very heavy figures of measurement,
As a proof
5.3358912000000000000 km / 300,000 km light speed / 365d / 24h / 60m /60s / 10mm = 564000Ty Orbit of Milky-way. So it is right and best way to do measurement of universe.
So seconds are first step of measurement, and If you will not use first step Then your measurement will not be acceptable. and 31536000Ts is a first step of successful measurement.
As a proof by Earth,
earth distance are 1752s x 10 x 100 x 1000 = 1752000000 x 3 angle of triangle = 5256000000 kilometres distance of earth from the sun. So 5256000000 / 300,000km light speed = 17520 / 4.8 Neutron energy = 3650 / 10mm = 365 days of earth
Orbit of Milky-way and date of today.
Milky-way Orbit is 1.7786304000000 seconds and we shall solve its through the Time year. So 1.7786304000000s / 1.491053678 H M** unit = 1.1928681220000 / 10512 Code = 1134768000 / 564000Ty = 2012 date of today. So the Milky-way orbit is 564000 Time-Year, or your complicated Light-year.
So Milky-way Orbit is contain on 564000-Time-year. and its radius is 94000-Time-year with 1000Ty thickness. and It was a basic measurement of Milky-way. Now how many stars are in the Milky-way. Although it is also a big question. we shall use Super-Diameter maths to which.
Super-Diameter.
Super-Diameter maths is a category of maths. which is used in many others planets. and I am first person, who introduction in the world.