Sikander aqeel

DISAPPEAR SCIENCE WITH BERKELIUM-247

Jun 4th 2012, 10:53 pm
Posted by aqeelsika1
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Possible Laws of Chemical Combinations. 

You knows very well, each metal cannot Chemical Combinations with other metal. because the temperature occurs different of each metal from each other. and It is important point for Chemical Combinations. So here we shall make some law of Chemical Combinations. 

 

 

1, High Chemical Combinations. 2, Automatically Chemical Combinations. 3, Two unit Chemical Combinations. 

 

 

High Chemical Combinations.      

High temperature + high mass unit = possible Chemical Combinations. like a Isotopes of Uranium. they can be easier made. because their system occurs equal of temperature and mass unit. So mostly metals are branches of High Chemical Combinations. which can be changed. So High Chemical Combinations is equal to Inner + outer temperature.   

 

 

Automatically Chemical Combinations. 

low temperature + low mass unit = possible chemical Combinations. like a H2 + O + low temperature = water. and it will be called the Automatically Chemical Combinations. because temperature of morning belongs low temperature. and Earth makes 99 percent water in morning. and the morning is a continuous process of earth. So Automatically Chemical Combinations is equal to outer temperature.  

 

 

Two unit Chemical Combinations. 

Unit one itself temperature + Unit one itself temperature = possible chemical Combinations. Like a Silver nitrate + Hydrochloric acid = (white Precipitate). So we shall say here, Temperature of (AgNO3) + Temperature of (HCI) are two unit of chemical Combinations. in which not need of outer temperature. So Two unit Chemical Combinations is equal to Inner temperature. 

 

 

Weight of per Atom. 

even in any atomic theory is very important weight of per atom. and you knows it very well. That I am doing solve your atomic theory. which was written by relation of Oxygen weight. To day I am doing solve of your atomic theory. by the mass unit of Oxygen. because only mass unit is a weight for you.  

 

 

High Chemical Combination.     

High Chemical Combinations is equal to Inner + outer temperature. 1000 Centigrade Inner + 1000 Centigrade outer = High Chemical Combinations. 

 

High Chemical Combinations. 

(1) weight of per atom. (2) 1000 Centigrade inner temperature of atom. (3) 1000 Centigrade outer temperature of atom. (4) 12.5 is mass unit of sun Hydrogen atom. (5) Mass unit of atom. (6) 100 Centigrade is a temperature of boiling water. 

 

 

 

Berkelium-247 by balance of Oxigen 

Berkelium atomic weight is 4.94 Milligrams. then 4.94 x 1000 x 1000 = 4940000 Centigrade temperature. when earth was separated from sun. So 4940000 / 12.5 = 395200 / 247 Berkelium = 1600 / 100 Boiling temperature of water = 16 Mass unit of Oxygen atom. So 4.94 Milligrams is a weight of per atom of Berkelium. and to which is a ratio with Oxygen atom 

 

 

Weight of Neutron and Proton. 

0.02 Micro-gram is weight of one Neutron, and 0.02 one Proton. which is ratio 1/50. So 1 / 50 = 0.02. Now what is the fifty. Actually the fifty is second basic value of each thing in the universe. or 1 is complete value of universe. but 50 is also a value of half period. So Berkelium mass unit is 247 x 0.02 Microgram = 4.94 Milligrams weight of Berkelium. because 4.94 x 50 = 247 mass unit of Berkelium. So 1/0.02 x 1/50 = weight and mass unit of atom. 

 

 

Total weight of Proton and Neutron. 

Berkelium atomic number is 97 x 0.02 = 1.94 Milligrams total weight of 97 proton of Berkelium. Now Berkelium Neutron are 150 x 0.02 = 3.00 Milligrams total weight of Neutron of Berkelium. after gather 1.94 + 3.00 = 4.94 miligrams weight of one Berkelium atom. because 4.94 x 50 = 247 mass unit of Berkelium. 

 

 

Disappear mass unit of atom. 

A mass unit contains Neutron and Protons numbers. or, mass unit is a heap of Neutron and Protons. and Neutron and protons weight is 0.02 Micro-gram. therefore one atom cannot be seen with normal condition. because atom is heap of Micro-gram. So the atom is a Disappear thing. But when some atom becomes gather in one place. that they becomes able of see. So the nearly one Fermium is disappear atom. Because Its weight is 5.06 Milligrams. But when we shall bring its into the gram. That Fermium will be able to see. 

 

Mass unit = gram, Weight = Milligrams, Neutron Proton = Micro-gram

One gram = 1 gram. 1000 milligrams = 1 gram. 1000000 Micro-gram = one Neutron . 1000000 Micro-gram = one Proton. after collect = 1000 x 1000000 x 1000000 = -1000000000000000. and it is weight of one gram. and it is disappear weight because it is into the minus condition reason of Milligrams and Micro-gram. or, the mass unit can be seen only in gram. and nor the shape of one atom, nor the Neutron and proton. So It is -1000000000000000 a weight. to which definition is Milligrams and Micro-gram. 

 

 

Molecular Number          

Time atomic weight x gram x Neutron x Proton = Molecular Number into the one gram. 

 

 

Molecular Number of Californium-251. 

Berkelium Time atomic weight is 4.94 Milligrams. then 4.94 x 1000 x 1000000 x 1000000 = 4.940000000000000, Molecules of Berkelium into the one gram. because these are in balance of Mass unit and Proton numbers. So 4.940000000000000 x 0.02 proton weight = 9.8800000000000 / 1000000 Neutron / 1000000 Proton = 98.8 - 1.8 Cross-pron = 97 Atomic Number of Berkelium-247. So one gram Berkelium is equal to 4.940000000000000, Moleculer weight. 

 

 

The Force of Chemical Bonds.  

and it is very important. because often you would have heard. that we cannot dissolve one metal in other metal. because occurs different bond value of each metal. 

 

 

What is the Chemical Bonds.  

Actually the Chemical bond is a value of milligrams weight of atom. and this value keeps set up of molecular system in the grams. or Chemical bond is a gravity of atom, which occurs affected by the weight of atom. So here we are becoming Bond atomic number.       

 

Chemical Bonds Value of one gram Berkelium-247. 

4940 per gram. because 4940 x 50 = 247000 / 1000 gram = 247 mass unit of Berkelium. 

 

 

 

Time Atomic Weight and bond number 

that system of measurement. which can be easily solved. and its definition is very simpler. that Atomic Weight is equal to total number of mass unit + total atomic number. Like a Berkelium Atomic Weight is 4.94 Milligrams. and it is very easy for understand. because there was used name of measurement for Berkelium weight. Like a 4.94 Milligrams Berkelium. 

 

 

and one gram is perfect value of measurement. 

Now we are taking of Berkelium into the one gram, for find out its mass unit and atomic number. So 4.94 x 1000 Milligrams = 4940. and it is a bond number only of Berkelium. So 4940 / 50 ratio = 98.8 - 1.8 Cross-pton = 97 Atomic Number. Now for Mass unit, 4940 x 50 ratio = 247000 / 1000 Milligrams = 247 Mass unit of Berkelium. 

 

 

So 4.94 Milligrams is a name of measurement. and if you does not write name of measurement for atom. then that weight would be come in the circle of doubt. So we shall write here, 4.94 milligrams is weight of Berkelium. In which are 150 Neutron and 97 proton. 

 

 

Energy of Chemical Bonds. 

which makes the bond of atoms for molecules. and it is not difficult for explain. So Chemical bond energy contains on two system of Proton and electron. (1) one electron charge always react of atom continuous. or one electron charge occurs divide from atom continuous for take new energy from proton of atom. or one electron, which becomes weak, 

 

 

that they fall on the surface of atom for again go back at the last orbit. and quantity of this process, happens different in each metals. Like a Iron can make sold block of 1000 kilograms through the molecular energy. but the gold cannot make own black of one kilograms. So when a electron fall down on the surface of atom. that other atom becomes include into the compound. 

 

 

By maths. 

one proton charge is 28.8, and 14.4 is charge of one electron. Now Berkelium atomic number is 97. and it will be called the atom. then 97 x 28.8 = 2793.6 / 14.4 = 194 two atom x 28.8 = 5587.2 / 14.4 = 388 four atom x 28.8 = 11174.4 / 14.4 = 776 eight atom x 28.8 = 22348.8 / 14.4 = 1552 sixteen atom x 28.8 = 44697.6 / 14.4 = 3104 thirty-two atom. So it was a chain of Chemical bonds to which is not any end into the universe. 

 

 

All metals belongs with each other. 

after the oxygen, the Mercury is second metal, to which ratio by the mass unit nearly same with each metal. So Berkelium mass unit is 247 / 6 radius = 41.16666667 and it is a radius of Berkelium and it is also a past. But we shall say here, 41.16666667 is a amount of one triangle. which are member of six triangle. because it is not in the weight. since it is in Micrometer. Now 41.16666667 / 4.94 weight = 8.333333333, So here 8.333333333 Micrometer are equal to 4.94 Milligrams. and it is a past of Mercury. because 8.333333333 x 24 hours for future = 200 mass unit of Mercury. So Berkelium is equal to Mercury. 

 

 

The bonds of Neutron and Proton into the Berkelium-247       

(1) We shall get one triangle here throught the radius laws. (2) and we shall more divide of one triangle with the Neutron value and proton value. (3) and we shall come back in future through the 24 hours. (4) and we shall be gotten a bond of some Neutron and Proton. (5) Neutron weight is 0.02 Micro-gram, and proton weight is 0.02 Micro-gram. 

 

 

For bonds number of Berkelium

So Berkelium mass unit is 247 / 6 radius = 41.16666667 / 5 photon of proton = 8.233333333 / 4 photon of neutron = 2.058333333 x 24 hours for future = 49.4 is a bond number for Berkelium atom. So 49.4 / 0.02 = 2470 / 10mg = 247 mass unit. and for atomic number. 49.4 x 0.02 = 0.988 x 100mg = 98.8 - 1.6 Cross-pton = 97 atomic number of Berkelium-247. So 49.4 are first basic bonds of neutron and Proton into the Berkelium-247. and 97 protons are a balance into the Berkelium-247. which makes a shape of atom by the numbers. 

 

The system of Chemical bonds of stars. 

The systen of stars chemical bond is taken into the heat of elements. This system keeps warm of star system by inner and outer. because occurs not element of proton into the stars. but there also in stars, happens three elements, Neutron, Cross-pton and Cross-tron of different type. 

 

 

The system of Chemical bonds of Planets. 

for planets, chemical bond law belongs with proton and electron charge. and this system attached with only planets. and it is second basic law, which makes the Planets into the universe from stars. and body of human is also a sample of chemical bond. but than in metals, our system of body some different, that in our system becomes early finish the period of proton from life. 

 

 

Californium-251 and total number of bonds. 

nearly 5 bonds completes one atom of Berkelium. Because the bonds system belongs with protons. and one proton contains on 5 photons. So one bond value of Berkelium is 49.4, or 12.35 Protons and 37.05 Neutrons makes one bond, to which value is 49.4. So 49.4 x 5 = 247 mass unit of Berkelium. and every 5 bond makes one atom in whole atomic theory, because this law belongs with atomic theory of planets. 

 

 

Power of Bond of Berkelium-247, 

one bond happens very powerful, which makes a atom or which completes one atom into own system. and from this reason, each metal never happens dissolves into other metal. So Berkelium bond number is 49.4. and which is contain on 12.35 protons and 37.05 Neutrons. 

 

 

By maths      

or 12.35 Proton / 50 = 0.247 x 1000mg = 247 mass unit of Berkelium. and 37.05 Neutron x 4 photons of Neutron = 148.2 + `1.8 Cross-pton = 150 Neutron of Berkelium and we shall say here, that power of bond of Berkelium is contain on the Neutron 150. Actually the bonds makes the atom. which happens very powerful in own numbers. So why never breaks one atom, because their bonds number occurs in very small size, like a 49.4 / 1000mg / 1000000mcg / 1000000mcg = 0.0000000000000494. So one atom can be broken easily. but never can be broken one bond of metal. 

 

 

 

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