THE ORBIT SOME WARM SUBSTANCE.
Now today we are Twenty-eight minute away from the sun. and we have 350 days of orbit or distance. and the universe divided in distance and time. If the planet weight too much, then they would be too away from the Sun. and they planets will be called the perfect planets. Like a Neptune, Saturn, Uranus, Jupiter, Earth, Venus and Mercury. and the Mars and Pluto are not perfacet planets into the solar system. or we can say here, that Mars and Pluto are mistakes of solar system. and both are in unbalance shape by distance.
and the universe is a sample of balance. like a “A’ is distance, then Planets and stars diameter and weight also would have “A” shape. and the human is also amde by this laws. or occurs weight of each distance into solar system and star system. So why earth days are 365 in year. because the distance is 365 days of earth. therefore the radius is equal to diameter, and diameter is equal to distance.
Rate of orbit.
we shall solve this matter with light speed. but you should know about light speed. and it is not very difficult. Number one, A star`s temperature of surface always happens 15000000 Centigrade. and always into one proton are happens five photons. and
the light speed begins from one meter, one seconds. when we shall divide the sun surface temperature with five photons. then one heated particle would be divided. and when we multiply with 100 centimetres. then will be begun the travel of ray.
First basic law.
Temperature of sun`s surface is ‘‘15000000 Centigrade’’ / 300000000 light speed per meter seconds = 0.05 x 100 centimetre = 5 photons of one proton.
Second basic law.
I know it that 0.05 is very cheap value of any mass. because it is the heat value of mass. and photons happens very small. to which you cannot see. only can be feel them. So one photon mass equal to .008. So then 0.05 / .008 = 6.25 / 1.25 Earth hydrogen mass unit = 5 photons of one proton.
Third basic law.
Temperature of sun`s surface is ‘‘15000000 Centigrade’’ / 12.5 mass unit of sun hydrogen atom = 1200000 x .008 hot photon = 9600 x .008 cold photon = 76.8 / 60 minute = 1.28 - 0.03 = 1.25 mass unit of earth`s hydrogen.
Fourth basic law. About light speed
Stars`s surface temperature 15000000 / 5 Photons or one Proton = 3000000 x 100 Centimetres = 300000000 light speed meter per seconds.
‘‘Twenty-eighth’’ Nearest Orbit OF Sun.
Sun`s ‘‘Twenty-eighth’’ orbit which belongs with living Particles. this orbit is ‘‘Twenty-eight’’ .minute far from sun. and ‘‘Twenty-eight’’ minute are equal to 1680 seconds. So 1680 x 300000000 = 5.04000000000 meters distance from sun. and to the know days 5.04000000000 / 24 hour / 60 minute / 1000000 light measure = 350 days of ‘‘Twenty-eight’’ minute distance from the sun.
Now to the orbit 5.04000000000 x 6 = 3.024000000000 meter orbit. to the know days 3.024000000000 / 24 hours / 360 degree / 1000000 light measurement = 350 days of ‘‘Twenty-eight’’ minute orbit of the sun.
Here is not present any satellite.
But I am doing solve value of each orbit. even which orbit is away from the sun. So it is ‘‘Twenty-eighth’’ orbit of sun. If in future you made a humans colony into space. then you can acquire the energy from even any orbit of sun.
Diameter of Satellite.
If the satellite diameter proper and perfect. then they will right rotate around the sun. and it is first important matter. because which you ll’ make the satellites to rotate around of sun. their size will nearly equal to 11.66 percent of moon of earth. So orbit radius or distance is 1680 light seconds between Orbit and sun. Now for get the diameter, If any satellite happens there.
So 1680 x 21.78 code of diameter = 36590.4 kilometres diameter of the satellite. and by radius that 36590.4 / 6 = 6098.4 kilometres radius. and it is 11.66 percent longe radius from our moon. because moon radius is 522.72 kilometre and after divide. satellite radius is 6098.4 / 522.72 = 11.66 percent satellite size would be big from the Moon. Now satellite total seconds are 1680 x 3.63kg length weight code = 6098.4 / 17.424 Code of days = 350 days of ‘‘Twenty-eighth’’ orbit of sun.
Diameter of Earth.
1752 is the distance of earth in the light seconds. So 1752 x 21.78 Code of diameter = 38158.56 kilometres. diameter of Earth. and radius is 6359.76 kilometres. or, 38158.56 / 6 = 6359.76 kilometres radius of earth. or, from easy maths. 1752 light seconds x 3.63kg length weight = 6359.76 kilometres radius. So 6359.76 / 17.424 Code of days = 365 days of Earth.
Earth size compare with moon.
The moon rasius is 522.72 kilometres and the earth radius is 6359.76 kilometres. then 6359.76 / 522.72 = 12.16 percent the earth is big from the our moon.
Temperature of satellite. By the earth.
We are doing compear of temperature with the Earth for each distance. So the earth temperature is 118.91 Centigrade, and Earth distance is 29.2 Minute far from the sun.
satellite. perhaps would have remember you that law of temperature. ( that light speed / distance in seconds / 24 hours / 60 minute = temperature of planet). So satellite or orbit`s radius is 1680 light seconds. Then 300000000 / 1680 = 178571.4286 / 24 = 7440.47619 / 60 = 124.0079365 Centigrade temperature will happen of satellite or of the ‘‘Twenty-eight’’ orbit. and it is right and perfect temperature. because when we ll’ divide with Venus temperature with the satellite or for the temperature of orbit.
then our proof will be strong. So satellite temperature is 124.0079365 / 118.91 = 1.04 x 28 minute = 29.12 - 0.1 = 29.02 minute distance of Earth from the sun. here we shall say. if your basic maths would have to be right. then you can solve each matter of universe. Now we have 124.007 Centigrade temperature to the satellite or of the orbit. If you are thinking that it is too much temperature. then you are wrong. because which maths I am going to tell you. that our problem will be solved About space.
Earth temperature:
300000000 / 1752 seconds distance = 171232.8767 / 24 hours = 7134.703196 / 60 minute = 118.91 temperature of earth. So water temperature 59.455 - 118.91 = 59.455 Centigrade temperature of earth
What is the gravity in universe.
As count this satellite will happen 11.66 percent big from our moon. which is important point here. The sun diameter is 4833.26 days kilometres. and it is a vast diameter. So 1680 seconds or 28 minute away from sun. we are doing calculation of which orbit. which is very close from the sun. from this reason that from here the very less rotation would have to be started. Or, you can multiplication of moon exis rotation from the 11.66
About mass reaction or gravity.
A exist in each planet, moon and stars the reaction of mass. but their value are different in our universe. I made a law for this. which is very easy. 1. FOR STAR, to the normal size`s star. the Mass reaction would to be 300,000. kilometres till from on surface. or one light seconds Mass reaction from on surface of the star. and. here are being some Misunderstanding. you would be wait for it.
The velocity of satellite in own orbit.
The satellite`s velocity will happen 35.80 kiometres per seconds in own orbit. and it velocity is 5 percent excessive from the sun diameter. So it is finally accurate law of velocity. Now to the make law we ll’ use the sun diameter and atom two conditions. So satellite days are 350 in own orbit. next 1.25 is warm condition of Hydrogen atom and 1.25 is cool condition of Hydrogen. after collect of both. 1.25 + 1.25 = 2.5.
Law of velocity
Now satellite total days are 350 / 2.5 = 140 and it is the code of speed. The sun diameter is 4833.26 days kilometres. So 4833.26 / 140 speed code = 34.52 kilometres per seconds speed of satellite. I had explained about velocity of planet 2.5 years ago. which
was sixth percent accurate. and it law is hundred percent accurate . Actually! I am explaining about many subject in same time. So can be mistake but I itself shall do accurate own each mistake. And in the beginning the Internet and english were new things for my.
Velocity of earth.
The Earth days are 365 / 2.5 = 146 and sun diameter 4833.26 / 146 = 33.10 kilometres per seconds velocity of Earth around the sun.