LAST ELECTRON OF ‘‘NEON’’ WITH CROSS-TRON

WITH ENERGY LAW  ‘‘E = m + m x C1’’

10 last electron of ‘‘Neon’’ Perhaps for this reason his says atomic number 10. Or` atomic number 10 meaning last electron of ‘‘Neon’’ So Electron number 10 have also one orbit. and his connect was also with sector 9000L like our earth. and` we shall solve motion of last electron with planets motion. we would be got here four information. (1) Electron energy. (2) Electron orbit. around the atom (3) micro meter distance between Electron and ‘‘Neon’’ level till. (4) micro seconds distance 

between Electron and ‘‘Neon’’ But before the begin. I want some tell you, about Atomic number. with a simple method. Our earth have 365 days, But` if sees to his, like a atomic theory. Then sun is like a atom and Earth is a Electron and his atomic number is 365. Perfectly like this ‘‘Neon’’ is a atom and his last electron is his atomic number 10 Last electron of ‘‘Neon’’ that in last Electron revolves around with micro meter speed. after of all.

EARTH HOT AND COLD PERIOD, 

So E = m + m x C1. Earth was hot in begin and Earth has cold now. m365 hot + m365 cold = 730 x C1 300000000 = 2.19000000000 x .008 photon = 1752000000 / 1000m / 100m /10mm = 1752 seconds distance between Earth and Sun. Now` we 

shall make his distance in meters and orbit. 1752 x 300000000 = 525600000000m and` it is distance in meters. 525600000000 x 6 = 3153600000000m and` it is orbit of Earth. Now` to this orbit` we shall do shift in atom number. (1) electron has not 

moon, (2) electron has not days months and year. from this reason` orbit of electron we shall divide with 24 hours and 360 degrees. 3153600000000m / 24 / 360 degrees = 365000000 / 1000m / 100m / 10mm = 365 atomic number. Or` 365 atomic number of Earth. now

LAST  ELECTRON OF ‘‘NEON’’ AND, E = m + m x C1. 

‘‘Neon’’ atomic number is 10. So m10 hot + m10 cold = 20 x C1, 300000000 = 6000000000 x .008 one photon = 48000000 / 1000m / 100m / 10mm = 48 is micro seconds distance between last electron. and 6600000000 volt energy of last 

electron of ‘‘Neon’’ Now` we shall make his distance in micro meter 48 x 300000000 =  14400000000 / 1000m / 100m /10cm = 14400 it is the distance in micro meters between last electron and ‘‘Neon’’ surface till. to the proof  14400  / 24 hours  / 60 minute 

= 10 electron of ‘‘Neon’’ Now` we shall make to his orbit. 14400  x 6 = 86400 so it is orbit  of last electron. in the micro meter measurement. (  Now for the atomic number ) we shall make his atomic number. 86400 orbit / 24 hours = 3600 / 360 degrees = 10 atomic Number of ‘‘Neon’’    

DETAILS OF ELECTRON OF ‘‘NEON’’          

(1) electron energy  6000000000 volt. (2) electron orbit 86400 micro meter. (3) 14400 is micro meter distance between last electron and ‘‘Neon’’ surface till. (4) 48 micro seconds distance between last electron and ‘‘Neon’’             

PROOF OF DETAILS.  

1. one electron charge 14.4 and one proton charge 25 percent excessive from electron. 

1. 6000000000 volt / 14.4 = 416666666.7 x .008 = 3333333.333 / 1000000 = 3, So 3 + 22 = 25 percent excessive charge of proton from one electron.

2. we shall compare between hydrogen size and electron charge. with micro meter distance 14400  

2. 14400  / 1.25 hydrogen size = 11520 / 60 seconds hydrogen time = 192 / 100 area =  1.92 + 12.48 = 14.4 electron charge.

3. orbit, we shall to know percentage of electron charge here. with photon quantity. in one proton happens 5 photons. 

3. 86400 / 5 = 17280 / 360 degrees = 48 / 25 proton percentage = 1.92 + 12.48 = 14.4 active charge of electron.  

4. we shall to know percentage of charge with proton charge 28.8. 

4. 48  micro meter distance. So 48  / 28.8 = 1.6 + 10.9 = 12.5 Sun hydrogen atom size  

LAST ELECTRON OF ‘‘NEON’’ AND CROSS-TRON.

If the electron charge value would be right. then will be solved automatically time of mass and weight of mass through the new energy law. So ‘‘Neon’’ atomic seconds distance 48  

and one electron charge 14.4 and energy law E = m + m x C1. Now, m14.4 + m48  = 62.4 x 300000000 = 28720000000 / 24 hours / 60 minute / 1000m / 100cm light measure = 130 / 65  light code = 2 Cross-tron of ‘‘Neon’’ Now to the work condition ‘‘Neon’’ will have need 65 volt 

energy for one atom and you will be get 6000000000 volt energy from one atom. But how` when we shall be reached at Hydrogen atom till then you will understood. and Every maths is possible If you have right atomic energy law. You know very well that i test at earth first of all. and second at atom. and third at human body.