Sikander aqeel

THE ‘‘TWENTY-FIFTH’’ ORBIT'' OF SUN

May 10th 2012, 9:48 pm
Posted by aqeelsika1
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THE ORBIT  SOME WARM SUBSTANCE.  

And It orbit is ‘‘Twenty-five’’ minute'' away from the sun. Now the orbit are happening cool from reason of distance. If the Dinosaur was expel out the Fire from mouth then they were belong with Mercury orbit. But it is some cool orbit of sun. So it is orbit of Lion and wolf types hot animals.

 

 

 

RATE OF ORBIT. 

we shall solve this matter with light speed. but you should know about light speed. and it is not very difficult. Number one, A star`s temperature of surface always happens 15000000 Centigrade. and always into one proton are happens five photons. and

 

 

 

the light speed begins from one meter, one seconds. when we shall divide the sun surface temperature with five photons. then one heated particle would be divided. and when we multiply with 100 centimetres. then will be begun the travel of ray.

 

 

 

FIRST BASIC LAW. 

Temperature of sun`s surface is ‘‘15000000 Centigrade’’ / 300000000 light speed per meter seconds = 0.05 x 100 centimetre = 5 photons of one proton.

 

 

 

SECOND BASIC LAW. 

I know it that 0.05 is very cheap value of any mass. because it is the heat value of mass. and photons happens very small. to which you cannot see. only can be feel them. So one photon mass equal to .008. So then 0.05 / .008 = 6.25 / 1.25 Earth hydrogen mass unit = 5 photons of one proton. 

 

 

 

THIRD BASIC LAW. 

Temperature of sun`s surface is ‘‘15000000 Centigrade’’ / 12.5 mass unit of sun hydrogen atom = 1200000 x  .008 hot photon = 9600 x .008 cold photon = 76.8 / 60 minute = 1.28 - 0.03 = 1.25 mass unit of earth`s hydrogen.

 

 

 

FOURTH BASIC LAW.  ABOUT LIGHT SPEED

Stars`s surface temperature 15000000 / 5 Photons or one Proton = 3000000 x 100 Centimetres = 300000000 light speed meter per seconds. 

 

 

 

‘‘TWENTY-FIFTH’’ NEAREST ORBIT OF SUN.  

Sun`s ‘‘Twenty-fifth’’ orbit which belongs with living Particles. this orbit is ‘‘Twenty-five’’ .minute far from sun. and ‘‘Twenty-five’’ minute are equal to 1500 seconds. So 1500 x 300000000 = 450000000000 meters distance from sun. and to the know days 450000000000 / 24 hour / 60 minute / 1000000 light measure = 312.5 days of  ‘‘Twenty-five’’ minute distance from the sun. 

 

 

 

Now to the orbit 450000000000 x 6 = 2700000000000 meter orbit. to the know days 2700000000000 / 24 hours / 360 degree / 1000000 light measurement = 312.5 days of ‘‘Twenty-five’’ minute orbit of the sun.  

 

 

 

NOT ANY SATELLITE EXIST HERE.

But I am doing solve value of each orbit. even which orbit is away from the sun. So it is ‘‘Twenty-five’’ orbit of sun. If in future you made a humans colony into space. then you can acquire the energy from even any orbit of sun. 

 

 

 

DIAMETER OF SATELLITE. 

If the satellite diameter proper and perfect. then they will right rotate around the sun. and it is first important matter. because which you ll’ make the satellites to rotate around of sun. their size will nearly equal to 10.41 percent of moon of earth. So orbit radius or distance is 1500 light seconds between Orbit and sun. Now for get the diameter, If any satellite happens there. 

 

 

 

So 1500 x 21.78 code of diameter = 32670 kilometres diameter of the satellite. and by radius that 32670 / 6 = 5445 kilometres radius. and it is 10.41 percent longe radius from our moon. because moon radius is 522.72 kilometre and after divide. satellite radius is 5445 / 522.72 = 10.41 percent satellite size would be big from the Moon. Now satellite total seconds are 1500 x 3.63kg length weight code = 5445 / 17.424 Code of days = 312.500 days of ‘‘Twenty-five’’ orbit of sun. 

 

 

 

DIAMETER OF EARTH. 

1752 is the distance of earth in the light seconds. So 1752 x 21.78 Code of diameter = 38158.56 kilometres. diameter of Earth. and radius is 6359.76 kilometres. or, 38158.56 / 6 = 6359.76 kilometres radius of earth. or, from easy maths. 1752 light seconds x 3.63kg length weight = 6359.76 kilometres radius. So 6359.76 / 17.424 Code of days = 365 days of Earth. 

 

 

 

EARTH SIZE COMPARE WITH MOON. 

The moon rasius is 522.72 kilometres and the earth radius is 6359.76 kilometres. then 6359.76 / 522.72 = 12.16 percent the earth is big from the our moon. 

 

 

 

TEMPERATURE OF SATELLITE. 

BY THE EARTH. 

We are doing compear of temperature with the Earth for each distance. So the earth temperature is 118.91 Centigrade, and Earth distance is 29.2 Minute far from the sun. 

 

 

 

satellite. perhaps would have remember you that law of temperature. ( that light speed / distance in seconds / 24 hours / 60 minute = temperature of planet). So satellite or orbit`s radius is 1500 light seconds. Then 300000000 / 1500 =  200000  / 24 = 8333333333 / 60 = 138.8888889 Centigrade temperature will happen of satellite or of the ‘‘Twenty-five’’ orbit. and it is right and perfect temperature. because when we ll’ divide with Venus temperature with the satellite or for the temperature of orbit. 

 

 

 

then our proof will be strong. So satellite temperature is 138.8888889 / 118.91 = 1.16 x 25 minute = 29 + .02 = 29.02 minute distance of Earth  from the sun. here we shall say. if your basic maths would have to be right. then you can solve each matter of universe. Now we have 138.88 Centigrade temperature to the satellite or of the orbit. If you are thinking that it is too much  temperature. then you are wrong. because which maths I am going to tell you. that our problem will be solved About space.  

 

 

EARTH TEMPERATURE: 

300000000 / 1752 seconds distance = 171232.8767 / 24 hours = 7134.703196 / 60 minute = 118.91 temperature of earth. So water temperature 59.455 - 118.91 = 59.455 Centigrade temperature of earth 

 

 

 

WHAT IS THE GRAVITY IN UNIVERSE. 

As count this satellite will happen 10.41 percent big from our moon. which is important point here. The sun diameter is 4833.26 days kilometres. and it is a vast diameter. So 1500 seconds or 25 minute away from sun. we are doing calculation of which orbit. which is very close from the sun. from this reason that from here the very less rotation would have to be started. Or, you can multiplication of moon exis rotation from the 10.41 

 

 

 

ABOUT MASS REACTION OR GRAVITY.  

A exist in each planet, moon and stars the reaction of mass. but their value are different in our universe. I made a law for this. which is very easy. 1. FOR STAR, to the normal size`s star. the Mass reaction would to be 300,000. kilometres till from on surface. or one light seconds Mass reaction from on surface of the star. and. here are being some Misunderstanding. you would be wait for it.  

 

 

 

THE VELOCITY OF SATELLITE IN OWN ORBIT. 

The satellite`s velocity will happen 38.66 kiometres per seconds in own orbit. and it velocity is 5 percent excessive from the sun diameter. So it is finally accurate law of velocity. Now to the make law we ll’ use the sun diameter and atom two conditions. So satellite days are 312.5 in own orbit. next 1.25 is warm condition of Hydrogen atom and 1.25 is cool condition of Hydrogen. after collect of both. 1.25 + 1.25 = 2.5.

 

 

 

LAW OF VELOCITY

Now satellite total days are 312.5 / 2.5 = 125 and it is the code of speed. The sun diameter is 4833.26 days kilometres. So 4833.26 / 125 speed code = 38.66 kilometres per seconds speed of satellite. I had explained about velocity of planet 2.5 years ago. which 

 

 

was sixth percent accurate. and it law is hundred percent accurate . Actually! I am explaining about many subject in same time. So can be mistake but I itself shall do accurate own each mistake. And in the beginning the Internet and english  were new things for my.

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