THE ORBIT OF SOME WARM SUBSTANCE.
And It orbit is Twenty-one minute'' away from the sun. Now the orbit are being cool from reason of distance. If the Dinosaur was expel out the Fire from mouth then they were belong with Mercury orbit. But it is some cool orbit of sun. So it is orbit of Lion and wolf types hot animals.
RATE OF ORBIT.
we shall solve this matter with light speed. but you should know about light speed. and it is not very difficult. Number one, A star`s temperature of surface always happens 15000000 Centigrade. and always into one proton are happens five photons. and
the light speed begins from one meter, one seconds. when we shall divide the sun surface temperature with five photons. then one heated particle would be divided. and when we multiply with 100 centimetres. then will be begun the travel of ray.
FIRST BASIC LAW.
Temperature of sun`s surface is ‘‘15000000 Centigrade’’ / 300000000 light speed per meter seconds = 0.05 x 100 centimetre = 5 photons of one proton.
SECOND BASIC LAW.
I know it that 0.05 is very cheap value of any mass. because it is the heat value of mass. and photons happens very small. to which you cannot see. only can be feel them. So one photon mass equal to .008. So then 0.05 / .008 = 6.25 / 1.25 Earth hydrogen mass unit = 5 photons of one proton.
THIRD BASIC LAW.
Temperature of sun`s surface is ‘‘15000000 Centigrade’’ / 12.5 mass unit of sun hydrogen atom = 1200000 x .008 hot photon = 9600 x .008 cold photon = 76.8 / 60 minute = 1.28 - 0.03 = 1.25 mass unit of earth`s hydrogen.
FOURTH BASIC LAW. ABOUT LIGHT SPEED
Stars`s surface temperature 15000000 / 5 Photons or one Neutron = 3000000 x 100 Centimetres = 300000000 light speed meter per seconds.
TWENTY-ONE NEAREST ORBIT OF SUN.
Sun`s Twenty-one orbit which belongs with living Particles. this orbit is ‘‘Twenty-one’’ minute far from sun. and ‘‘Twenty-one’’ minute are equal to 1260 seconds. So 1260 x 300000000 = 378000000000 meters distance from sun. and to the know days 378000000000 / 24 hour / 60 minute / 1000000 light
measure = 262.5 days of ‘‘Twenty-one’’ orbit of sun. Now to the orbit 378000000000 x 6 = 2268000000000 meter orbit. to the know days 2268000000000 / 24 hours / 360 degree / 1000000 light measurement = 262.5 days of ‘‘Twenty-one’’ orbit of the sun.
NOT ANY SATELLITE EXIST HERE.
But I am doing solve value of each orbit. even which orbit is away from the sun. So it is ‘‘Twenty-one’’ orbit of sun. If in future you made a humans colony into space. then you can acquire the energy from even any orbit of sun.
DIAMETER OF SATELLITE.
If the satellite diameter proper and perfect. then they will right rotate around the sun. and it is first important matter. because which you ll’ make the satellites to rotate around of sun. their size will nearly equal to 8.75 percent of moon of earth. So orbit radius or distance is 1260 light seconds between Orbit and sun. in which
satellite will be sent. So 1260 x 21.78 code of diameter = 27442.8 kilometres diameter of the satellite. and by radius that 27442.8 / 6 = 4573.8 kilometres radius. and it is 8.75 percent longe radius from our moon. because moon radius is 522.72 kilometre and after divide. satellite radius is 4573.8 / 522.72 = 8.75 percent satellite size would be big from the Moon. Now satellite total seconds are 1260 x 3.63kg length weight code = 4573.8 / 17.424 Code of days = 262.5 days of ‘‘Twenty-one’’ orbit of sun.
DIAMETER OF EARTH.
1752 is the distance of earth in the light seconds. So 1752 x 21.78 Code of diameter = 38158.56 kilometres. diameter of Earth. and radius is 6359.76 kilometres. or, 38158.56 / 6 = 6359.76 kilometres radius of earth. or, from easy maths. 1752 light seconds x 3.63kg length weight = 6359.76 kilometres radius. So 6359.76 / 17.424 Code of days = 365 days of Earth.
EARTH SIZE COMPARE WITH MOON.
The moon rasius is 522.72 kilometres and the earth radius is 6359.76 kilometres. then 6359.76 / 522.72 = 12.16 percent the earth is big from the our moon.
TEMPERATURE OF SATELLITE.
BY THE EARTH.
We are doing compear of temperature with the Earth for each distance. So the earth temperature is 118.91 Centigrade, and Earth distance is 29.2 Minute far from the sun.
satellite. perhaps would have remember you that law of temperature. ( that light speed / distance in seconds / 24 hours / 60 minute = temperature of planet). So satellite or orbit`s radius is 1260 light seconds. Then 300000000 / 1260 = 2380952381 / 24 = 9920.634921 / 60 = 165.3439153 Centigrade temperature will happen of satellite or of the ‘‘Nineteenth’’ orbit. and it is right and perfect temperature. because when we ll’ divide with Venus temperature with the satellite or for the temperature of orbit.
then our proof will be strong. So satellite temperature is 165.3439153 / 118.91 = 1.39 x 21 minute = 29.19 - 0.17 = 29.02 minute distance of Earth from the sun. here we shall say. if your basic maths would have to be right. then you can solve each matter of universe. Now we have 165.34 Centigrade temperature to the satellite or of the orbit. If you are thinking that it is too much temperature. then you are wrong. because which maths I am going to tell you. that our problem will be solved About space.
EARTH TEMPERATURE:
300000000 / 1752 seconds distance = 171232.8767 / 24 hours = 7134.703196 / 60 minute = 118.91 temperature of earth. So water temperature 59.455 - 118.91 = 59.455 Centigrade temperature of earth
WHAT IS THE GRAVITY IN UNIVERSE.
As count this satellite will happen 8.75 percent big from our moon. which is important point here. The sun diameter is 4833.26 days kilometres. and it is a vast diameter. So 1200 seconds or 21 minute away from sun. we are doing calculation of which orbit. which is very close from the sun. from this reason that from here the very less rotation would have to be started. Or, you can multiplication of moon exis rotation from the 8.75
ABOUT MASS REACTION OR GRAVITY.
A exist in each planet, moon and stars the reaction of mass. but their value are different in our universe. I made a law for this. which is very easy. 1. FOR STAR, to the normal size`s star. the Mass reaction would to be 300,000. kilometres till from on surface. or one light seconds Mass reaction from on surface of the star. and. here are being some Misunderstanding. you would be wait for it.
THE VELOCITY OF SATELLITE IN OWN ORBIT.
The satellite`s velocity will happen 46.03 kiometres per seconds in own orbit. and it velocity is 5 percent excessive from the sun diameter. So it is finally accurate law of velocity. Now to the make law we ll’ use the sun diameter and atom two conditions. So satellite days are 262.5 in own orbit. next 1.25 is warm condition of Hydrogen atom and 1.25 is cool condition of Hydrogen. after collect of both. 1.25 + 1.25 = 2.5.
LAW OF VELOCITY
Now satellite total days are 262.5 / 2.5 = 105 and it is the code of speed. The sun diameter is 4833.26 days kilometres. So 4833.26 / 105 speed code = 46.03 kilometres per seconds speed of satellite. I had explained about velocity of planet 2.5 years ago. which
was sixth percent accurate. and it law is hundred percent accurate . Actually! I am explaining about many subject in same time. So can be mistake but I itself shall do accurate own each mistake. And in the beginning the Internet and english were new things for my.
VELOCITY OF EARTH.
The Earth days are 365 / 2.5 = 146 and sun diameter 4833.26 / 146 = 33.10 kilometres per seconds velocity of Earth around the sun.
THE SIZE OF SUN FROM ‘‘Twenty-one’’ MINUTE DISTANCE.
It is also very important matter. you always see the sun in 1.5 feet size from the earth. but if you want imagin size of sun from ‘‘Twenty-one’’ minute away. then this law will help us. many events rises up into the Universe. sometimes a star suddenly very quickly melt to be the small size. fact about a star. which was against across of our solar system in
the milky-way. and around this star the life were present in two planets. there in only four centuries. their star was fifty percent melt. from this reason. there life was suddenly finished into the two planets. why it happened, actually you do not know about the StarQuake which happens very dangerous. tell later to which details. So we are doing probe orbit of sun
from ‘‘Twenty-one’’ minute away. So from ‘‘Twenty-one’’ minute away the sun size will happen 2.5 feet. Now by maths that the sun diameter is 4833.26 days kilometres. So 4833.26 / 1260 seconds = 3.835920635 and we shall only use 3 here. So 3 x 10 atom = 30 inch size of sun from on ‘‘Twenty-one’’ minute away. and by the feet that 30 inch / 12 = 2.5 feet height of sun from ‘‘Twenty-one’’ minute away. or, size of sun.
WHY EARTH DAY ARE CONTAIN 24 HOURS.
WHAT IS THE VALUE OF 60 MINUTE BY HOURS
So we should know that what is the value of 60 minute and why one day of earth is equal to 24 hours. or what is the value of one minute into the universe. or 60 minute is only a way for find the hours. but we need a axis rotation of planet into the hours.
LAW OF AXIS ROTATION.
Actually the matter of axis rotation belongs with time and Super Code of rotation. So we shall find the Super Code for solve of axis rotation. So Earth rotation Code is 1.2,, Mars rotation Code is 1.1,, Jupiter rotation Code is 3.85,, Saturn rotation Code is 5.375,, Uranus rotation Code is 4.91,, Neptune rotation code is 3.34,, and Pluto rotation Code is 2.41,, ( and 60 minute are basic limit of one hour )
AXIS ROTATION AND 365 DAYS OF EARTH.
So Earth distance is 1752 light seconds from the sun. then 1752 / 1.2 Code = 1460 / 60 = 24.33 hours. So the 24.33 hours are value of axis rotation for complete one day of Earth.
AXIS ROTATION AND 365 DAYS OF EARTH.
Now one Proton is contain on five photon. and proton is electrical active substance into the space. So Axis rotation = one Proton and one Proton = five photon.
and if the zero minute is a distance of planet. then we shall write 0 - 5 = 5 Axis rotation of planet. if the 1 minute is distance of planet, then we shall write 1 - 5 = 4 Axis rotation of planet. So Earth distance is 29.2 minute then 29.2 - 5 photon of Proton = 24.2 hours Axis rotation of earth.
Now as a proof. 29.2 / 24.2 = 1.2o661157 Code. now earth light seconds are 1752. So 1752 / 1.2o661157 Code = 1452 / 60 second = 24.20000001 hour Axis rotation by the seconds. or 24.2 hour axis rotation of earth. because the Axis rotation is only reaction of distance. So if the distance would be too much. then axis rotation would be also too much of planet.
AXIS ROTATION AND 30 DAYS OF M00N OF EARTH
Moon days are 30 / 2.5 = 12 / 60 minute = 0.2 x 10 = 2 hours, or moon axis rotation is two hour per day. and this law only moon of planets.
AXIS ROTATION OF SATELLITE.
So 21 minute distance of satellite, then 21 / 16 hours for time Code = 1.3125 So 1260 light seconds of satellite and Satellite Code is 1.3125 then 1260 / 1.3125 = 960 / 60 = 16 hour,, or satellite rotation would be 16 hour per day. and this rotation is four percent much from the Venus rotation.
AS A PROOF.
Now we have 360 degrees of any circle, and this 360 degrees belongs with a pair, like one day of 24 hours, and a night of 24 hours, or 24 up degree, and 24 down degrees. or 0 to 180 degrees equal to day, or up side. and 180 to 0 equal to night, or down side. but the value of same of both. So by the axis rotation 24 hours are equal to one day. and 24 hours are equal to one night. but you do the count the day of 12 hours, and night of 12 hours. Actually yours dating system is wrong.
NOW ABOUT 262.5 DAYS OF SATELLITE.
262.5 / 360 = 0.729166666 x 24 part of first pair = 17.5 and it is axis rotation. So 17.5 x 24 part of second pair = 420 / 1.6 = 262.5 days of the orbit of satellite.
SECOND PROOF BY EARTH.
365 / 360 = 1.013888889 x 24 hours = 24.33333333 x 4.8 one neutron energy = 116.8 / 4 photon of one neutron = 29.2 minute distance of earth from the sun. and it is a relation between the axis rotation and the distance of earth.
NOW ABOUT 262.5 DAYS OF SATELLITE.
262.5 / 360 = 0.729166666 x 24 hours = 17.5 x 4.8 one neutron energy = 84 / 4 photon of neutron = 21 minute distance of orbit from the sun. So this law will be called the measurement of distance through the minute